Also
   I. (= >./) expr
gives all indices of the maximum, if you ever need that.

-- 
Raul



On Thu, Jun 12, 2014 at 2:39 AM, R.E. Boss <[email protected]> wrote:

> (i.>./)  gives the (first) index of the maximum.
>
>
> R.E. Boss
>
> (Add your info to http://www.jsoftware.com/jwiki/Community/Demographics )
>
>
>
> > -----Original Message-----
> > From: [email protected] [mailto:programming-
> > [email protected]] On Behalf Of Jon Hough
> > Sent: donderdag 12 juni 2014 7:37
> > To: [email protected]
> > Subject: [Jprogramming] Maximum totient ratio
> >
> > Another Project Euler...
> >
> > This time PE #69:  http://projecteuler.net/problem=69
> >
> > Essentially, find n which has the maximum of n/totient(n), for all
> positive
> > integers, n, up to 1000000.
> >
> > At first this seemed easy. I have a verb to calculate the ratio:
> > totient=: (- ~:)&.q:
> > func =.   ] % totient
> > then I can find the maximum:
> > max=. (>./)"1@:((] % totient)"0)
> >
> > max 1+i.1000000
> > 5.53939
> > But this gives me the ratio. I need to find n.
> > This is a problem, because finding the maximum, the verb, >./ , collapsed
> the
> > array so I don't think I can use I. or similar verb to get the index
> which
> gave
> > the maximum ratio. So I am not sure how to find the n which gave this
> ratio.
> >
> > A second issue is I think my method seems to not be well thought out
> > memory-wise. My method first calculates the ratio for every integer up to
> 1
> > million and holds them all in memory. Surely a better way would be to do
> > them one at a time and find the maximum as we go.
> > In J I am not sure how to do this. I am guessing the recursion verb $:
> will need
> > to be used.
> > Any help appreciated.
> > Regards.
> > ----------------------------------------------------------------------
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