The J is a little out of my league, but for non-integers, youcould use Binomial 
Theorem, as I said.(http://en.wikipedia.org/wiki/Binomial_series)
e.g.
e^pi = (1+(e-1))^pi   =  1+ pi*e + pi*(pi - 1)*e*e/2! +...
There's no exponentiation and you can calculate to arbitrary precision.

> Date: Tue, 5 Aug 2014 05:33:42 -0700
> From: [email protected]
> To: [email protected]
> Subject: Re: [Jprogramming] Power for the powerless
> 
> "A really simple approach would be "
> 
> for integer powers,
> 
> pow =: [: */ #~
> 
> 
> 
> 
> ----- Original Message -----
> From: Raul Miller <[email protected]>
> To: Programming forum <[email protected]>
> Cc: 
> Sent: Tuesday, August 5, 2014 2:36:53 AM
> Subject: Re: [Jprogramming] Power for the powerless
> 
> A really simple approach would be to use T.
> 
>    pow=: ^ T. 99
> That gives you a polynomial expression
> 
> 
> Here's a shorter version:
> 
>    ^ T. 4
> 
> 1 1 0.5 0.16666666666666666&p.
> 
> Here's the more accurate version:
> 
>    (^ -: pow) 10 11 12
> 
> 1
> 
> 
> It's not necessarily efficient, but it's really simple.
> 
> 
> Thanks,
> 
> 
> -- 
> 
> Raul
> 
> 
> 
> On Tue, Aug 5, 2014 at 1:01 AM, Dan Bron <[email protected]> wrote:
> 
> > That's a long page, but in brief: can you calculate the power series
> > without using ^ explicitly or implicitly (e.g. via t. or #: etc)?  Are all
> > the ^s I see in those power series easily replaced by instances of
> > */@:#"0  ?
> >
> > In other words, does that page teach me how to do the trick when literally
> > the only mathematical functions in my toolbox are (dyads) + - * % and
> > (monad) | ?
> >
> > -Dan
> >
> > ----- Original Message ---------------
> >
> > Subject: Re: [Jprogramming] Power for the powerless
> >    From: Roger Hui <[email protected]>
> >    Date: Mon, 4 Aug 2014 21:51:08 -0700
> >      To: Programming forum <[email protected]>
> >
> > ?Can you not just use power series (for both exp and ln)?  See
> > http://www.jsoftware.com/jwiki/Essays/Extended%20Precision%20Functions .?
> >
> >
> > On Mon, Aug 4, 2014 at 9:39 PM, Dan Bron <[email protected]> wrote:
> >
> > > There's a StackExchange puzzle which challeges us to implement power
> > (i.e.
> > > dyad ^) using only the simple arithmetic dyads + - * % and monad | [1].
> > In
> > > other words, we may not use ^ or ^. or variants.  There are still several
> > > open questions on the puzzle, not least of which involves the domain of
> > > the inputs (can the base be negative?) and range of the outputs (how much
> > > precision is required?), but neverthless we can make some assumptions and
> > > start to sketch an approach.
> >
> >
> > ----------------------------------------------------------------------
> > For information about J forums see http://www.jsoftware.com/forums.htm
> 
> 
> 
> >
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
> 
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