Joe, hope this helps to clarify… Bill was suggesting this…/Rob

   arr=:10 $ > ;: 'ab cd yyy jcd'
   arr
ab 
cd 
yyy
jcd
ab 
cd 
yyy
jcd
ab 
cd 
   'cd' E."1 arr
0 0 0
1 0 0
0 0 0
0 1 0
0 0 0
1 0 0
0 0 0
0 1 0
0 0 0
1 0 0
   +./"1 'cd' E."1 arr
0 1 0 1 0 1 0 1 0 1


On 28 Aug 2014, at 10:12 pm, Joe Bogner <joebog...@gmail.com> wrote:

> Tracy - symbols are a good way to go. Thanks for reminding me of them.
> 
> Raul - that's what I was missing... I needed to use e. with the same
> shape: eg.  arr e. (1 3 $ 'ab ')... Thank you.  Your examples are nice
> and generic and faster than -:"1
> 
> ...
> bill - Not sure what to do with E.
> 
> Bjorn - 'ab' I. arr doesn't seem to help either... I was hoping for a
> mask of 0 1 0 1 for whether it was found or the indices
> 
> On Thu, Aug 28, 2014 at 7:56 AM, Björn Helgason <gos...@gmail.com> wrote:
>> 'ab' I. arr
>> 
>> __-------------------_
>> https://groups.google.com/forum/m/#!forum/havaogskulamal
>> On 28 Aug 2014 10:58, "Joe Bogner" <joebog...@gmail.com> wrote:
>> 
>>> Apologies for the extremely basic question, but I am struggling with
>>> this after searching NuVoc and the dictionary.
>>> 
>>> How do I locate all the indices of 'ab' in arr?
>>> 
>>> arr=:10 $ > ;: 'ab cd yyy'
>>> 
>>> surely this isn't the best way:
>>> 
>>> ] (3 = +/"1 'ab' i. arr) # arr
>>> ab
>>> ab
>>> ab
>>> ab
>>> 
>>> 
>>> I have been primarily dealing with boxed strings up to this point,
>>> which seemed easier since it was locating an atom in a list, not a
>>> list in a table (practicing my vocabulary here... I might be wrong
>>> though)
>>> 
>>> 
>>> Thanks,
>>> Joe
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>>> 
>> ----------------------------------------------------------------------
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> ----------------------------------------------------------------------
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