If one can take 2 3 5 and 3 5 7 as given, this might do: */2 3 5x (^ ,: ^~) 3 5 7x
If it was "do this for the first N primes", it would be a little more complicated. On 2014.10.17 18:30:14, you, the extraordinary Kip Murray, spake thus: > > 72 30375 1313046875 > > The first of these numbers is (2^3) * (3^2) , the second is (3^5) * (5^3), > and the third is (5^7) * (7^5) . You see the pattern involving successive > primes. > > Write a J expression to produce the above list. --Kip Murray > -- Nollaig MacKenzie http://www.yorku.ca/nollaig ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
