> When I feel like programming defensively, I'll ensure that the last character
is LF (and remove any CRs) like this:
This is done by freads, unlike fread which returns the raw data.
On Tue, Nov 25, 2014 at 7:44 AM, Devon McCormick <devon...@gmail.com> wrote:
> I usually split on the last character using "cut" like this:
>
> <;._2 fread 'some.file'
>
> When I feel like programming defensively, I'll ensure that the last
> character is LF (and remove any CRs) like this:
>
> <;._2 LF (],[#~[~:[:{:]) CR-.~]0 : 0
> Four-score and seven years ago,
> our fathers brought forth upon this continent
> a new nation,
> conceived in liberty
> and dedicated to the proposition
> that all men are created equal.
> )
>
>
> On Tue, Nov 25, 2014 at 10:26 AM, 'Pascal Jasmin' via Programming <
> programm...@jsoftware.com> wrote:
>
> > The spec (Fasta) can be revised to splitting on all LFs, where the first
> > box is the control data, and subsequent boxes are the package.
> >
> > http://rosalind.info/glossary/fasta-format/
> >
> > If so, you can grab all of the records from the sample link with this
> > expression (copy records on clipboard, uses j8 clipboard access)
> >
> > cutLF each '>' cut wdclippaste ''
> >
> > The reason for the LFs in the payload as I understand it is to separate
> it
> > into processing chunks. Having them boxed works for this, but if you
> ever
> > need to put the LFs back, or join them into a single string
> >
> > LF joinstring ;/ 'abc'
> > a
> > b
> > c
> >
> > '' joinstring ;/ 'abc'
> > ; ;/ 'abc' NB. or this
> > abc
> >
> >
> > to extend Joe's solution
> >
> > (>@:{. ; ;@}.)@:cutLF each '>' cut
> >
> >
> >
> >
> > ----- Original Message -----
> > From: Joe Bogner <joebog...@gmail.com>
> > To: programm...@jsoftware.com
> > Cc:
> > Sent: Tuesday, November 25, 2014 6:00 AM
> > Subject: Re: [Jprogramming] Split on first found character
> >
> > I might do it this way:
> >
> > (>@:{. ; ;@}.)@(LF&cut) x
> >
> > ┌───────┬─────────────┐
> >
> > │case_id│GCTAGTCGACGTC│
> >
> > └───────┴─────────────┘
> >
> >
> >
> >
> > On Tue, Nov 25, 2014 at 5:47 AM, Jan-Pieter Jacobs <
> > janpieter.jac...@gmail.com> wrote:
> >
> > > I think I would solve it like this (with intermediate steps):
> > >
> > > x=: 'case_id', LF, 'GCTAGTCG', LF, 'ACGTC', LF
> > >
> > > NB. Find the locations of LF's in the string
> > > (LF = ]) x
> > >
> > > NB. assign 0 to everything before the LF, assign 1 to everything after
> it
> > > ([: +./\ LF = ]) x
> > >
> > > NB. The wonderful "key" adverb lets you apply verbs based on it's key
> > > (another array), eg. box
> > > (</.~ [: +./\ LF =]) x
> > >
> > > NB. Get rid of the LF's by replacing < by a version removing LF:
> > > ((<@#~ LF~:])/.~ [: +./\ LF = ]) x
> > >
> > > This is what I came up with, but smarter people will probably suggest
> > more
> > > elegant ways.
> > >
> > > I hope this is useful.
> > > Jan-Pieter
> > >
> > > 2014-11-25 11:00 GMT+01:00 Ryan <rec...@bwh.harvard.edu>:
> > >
> > > > I have a character array with LF's, and want to split it on the
> > > > first LF, and remove the remaining LF's. I'm wondering if there's a
> > > > simpler
> > > > way than what I'm doing now:
> > > >
> > > > x=: 'case_id', LF, 'GCTAGTCG', LF, 'ACGTC', LF
> > > >
> > > > filterLF=: #~ ~:&LF
> > > > headLF=: {.~ i.&LF
> > > > tailLF=: }.~ i.&LF
> > > > (headLF ; filterLF@tailLF) x
> > > > ┌────────┬─────────────┐
> > > > │>case_id│GCTAGTCGACGTC│
> > > > └────────┴─────────────┘
> > > >
> > > > (I'm reading text files in fasta format:
> > http://rosalind.info/glossary/
> > > > fasta-format/)
> > > >
> > > > Thanks for any suggestions,
> > > > Ryan
> > > >
> > > >
> > > >
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>
> --
> Devon McCormick, CFA
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