Henry
isnotreal =. ~:~ +
This is not the definition that Lippu used. It was:
(~:+) A=:(i:2)j./i:2
I also used A ~:+ A
Can they be considered a test for whether the numbers are complex?
Linda
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Henry Rich
Sent: Saturday, November 29, 2014 11:23 PM
To: [email protected]
Subject: [Jprogramming] Complex puzzle WAS: Better way to locate coomplex or
real numbers in an array
Two ways of detecting complex numbers have been suggested:
iscomplex =. 0 ~: 11&o.
isnotreal =. ~:~ +
They are not equivalent.
iscomplex a
1
isnotreal a
0
What is an example for the finite number a?
Henry Rich
On 11/29/2014 10:20 PM, Linda Alvord wrote:
\Very nice. Or, if it has a different conjugate it must be complex.
Linda
-----Original Message-----
From: <mailto:[email protected]>
[email protected]
[ <mailto:[email protected]>
mailto:[email protected]] On Behalf Of Lippu
Esa
Sent: Saturday, November 29, 2014 4:37 PM
To: '[email protected]'
Subject: Re: [Jprogramming] Better way to locate coomplex or real
numbers in an array
A real number equals its conjugate, so (~:+) works too:
]A=:(i:2)j./i:2
_2j_2 _2j_1 _2 _2j1 _2j2
_1j_2 _1j_1 _1 _1j1 _1j2
0j_2 0j_1 0 0j1 0j2
1j_2 1j_1 1 1j1 1j2
2j_2 2j_1 2 2j1 2j2
(~:+) A
1 1 0 1 1
1 1 0 1 1
1 1 0 1 1
1 1 0 1 1
1 1 0 1 1
Esa
-----Original Message-----
From: <mailto:[email protected]>
[email protected]
[ <mailto:[email protected]>
mailto:[email protected]] On Behalf Of Henry
Rich
Sent: 29. marraskuuta 2014 05:34
To: <mailto:[email protected]> [email protected]
Subject: Re: [Jprogramming] Better way to locate coomplex or real
numbers in an array
]A=:(i:2)j./i:2
_2j_2 _2j_1 _2 _2j1 _2j2
_1j_2 _1j_1 _1 _1j1 _1j2
0j_2 0j_1 0 0j1 0j2
1j_2 1j_1 1 1j1 1j2
2j_2 2j_1 2 2j1 2j2
(0 ~: 11&o.) A
1 1 0 1 1
1 1 0 1 1
1 1 0 1 1
1 1 0 1 1
1 1 0 1 1
Henry Rich
On 11/28/2014 10:27 PM, Linda Alvord wrote:
A is an array of real and complex numbers. Is there an easier way to
locate all the complex numbers. Signum locates each numbers
intersection with a line from it to the origin and the circle.
]A=:(i:2)j./i:2
_2j_2 _2j_1 _2 _2j1 _2j2
_1j_2 _1j_1 _1 _1j1 _1j2
0j_2 0j_1 0 0j1 0j2
1j_2 1j_1 1 1j1 1j2
2j_2 2j_1 2 2j1 2j2
*A
_0.707107j_0.707107 _0.894427j_0.447214 _1 _0.894427j0.447214
_0.707107j0.707107
_0.447214j_0.894427 _0.707107j_0.707107 _1 _0.707107j0.707107
_0.447214j0.894427
0j_1 0j_1 0 0j1 0j1
0.447214j_0.894427 0.707107j_0.707107 1 0.707107j0.707107
0.447214j0.894427
0.707107j_0.707107 0.894427j_0.447214 1 0.894427j0.447214
0.707107j0.707107
-.(*A)e. _1 0 1
1 1 0 1 1
1 1 0 1 1
1 1 0 1 1
1 1 0 1 1
1 1 0 1 1
I am looking for the best way to locate all the complex numbers.
Linda
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