Is it possible to define f tacitly?
f=: 3 : '({.@:>@:{.y)`:0 (>@:}.y)'
f (+:`*:;i.5)
0 2 4 6 8
It's meant to take the first gerund from a box that contains a list of
gerunds and data to operate on
It's an odd circumstance that needed it. I could probably rework the
logic but now I'm curious if it can be done
Some things I tried:
a=:(+:`*:;i.5)
f1=:{.@:>@:{.
f1 a
┌──┐
│+:│
└──┘
f2=:>@:}.
f2 a
0 1 2 3 4
Tried various version of combining f1 and f2 to no avail
This works:
g`:0 f2 a [ g=. f1 a
0 2 4 6 8
I'm thinking there might be a way to do it without the assignment?
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