Hey Rob, x: converts from standard precision to extended precision. The problem lies in the fact that 1e23 is a float, and as such can not exactly represent the number 10^23, and the precision is already lost there.
The solution is using extended precision values to start with: 10x^23 100000000000000000000000 Jan-Pieter 2015-05-26 11:34 GMT+02:00 Rob B <[email protected]>: > Hi, > > No doubt this has come up before but I cannot find any reference > > Could someone explain this please? > > x: 1e22 > 10000000000000000000000 > x: 1e23 > 99999999999999991611392 > > Regards Rob. > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
