Well, hmm... you can use an explicit wrapper:
A=:".;._2]0 :0
0 0 0.034
1 25 0.059
1.4 55 0.094
2 85 0
)
B=:|:4#,:2 2 1
B 4 :'x}y'"1 _|:A
0.034 0.059 0.094 0
0.034 0.059 0.094 0
0 25 55 85
But you can also accomplish the same thing with a gerund:
0&{::`(1&{::)}"1 B;"1 _ |:A
0.034 0.059 0.094 0
0.034 0.059 0.094 0
0 25 55 85
That said, I guess it is significant that the relevant rank here ("1
_) is applied to the boxer and the unboxer just uses "1 (because that
reflects the organization of the boxes).
Good enough?
Thanks,
--
Raul
On Wed, Aug 12, 2015 at 6:47 PM, Henry Rich <[email protected]> wrote:
> I still don't see how you get a rank on m.
>
> You can't use an x argument, because then you'd be doing dyad m}. And in
> the gerund form,
>
> (v1`v2)} y is (v1 y)} (v2 y)
>
> and you can't put a rank on the selection operation that way either.
>
> Henry Rich
>
> On 8/12/2015 10:41 AM, Raul Miller wrote:
>>
>> Oops, I overlooked that issue.
>>
>> But of course, there is a way of giving rank to m - you just have to
>> change the expression (use gerund form of } which extracts m out as an
>> argument, for example).
>>
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