Or

$>a0;a1;a2;a3

4 3


,/ on a list has no effect, unless the list has just one item.


Henry Rich

On 1/5/2016 10:44 PM, Devon McCormick wrote:
    'a0 a1 a2 a3'=. i.4 3
    $>,/a0;a1;a2;a3
4 3


On Tue, Jan 5, 2016 at 7:00 PM, bill lam <[email protected]> wrote:

for looping, try an accumulator, eg
a=. i.0 0

a=. a, a0
a=. a, a1
....
On Jan 6, 2016 2:21 AM, "PackRat PackRat" <[email protected]> wrote:

I do a lot of manipulations with stock market data and such (i.e.,
tabular data), and I often have to "rip apart" a table and then
reassemble the rows again.  The ripping apart is easy, but I've always
been challenged when putting it back together because the result never
came out the way I wanted (or expected).  After much experimenting and
mucking around, I came up with this (as an example):

     z=. (((a0 ,: a1) , a2) , a3) , a4    NB. "glue" rows together

However, there always seems to be a better way to do things in J.  Can
anyone enlighten me with an improved explicit manner (NOT tacit) of
doing this?  Thanks in advance!


Harvey
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