[Sorry, that was a mistake. This is a resend]

   #@:>@:;:'a man a plan a canal'     NB. 1
6
   #@:>@;:'a man a plan a canal'     NB. 2
6
   #@>@;:'a man a plan a canal'     NB. 3
1 3 1 4 1 5
   #@>@:;:'a man a plan a canal'     NB. 4
1 3 1 4 1 5
   #@(>@:;:)'a man a plan a canal'     NB. 5
6
   #@(>@;:)'a man a plan a canal'     NB. 6
6

These examples are hard for me to grok.
Comparing 1 and 2 and 4 suggests that either order is important or that #
is effected and > is not.
Example 6 suggests that parentheses can produce results like @: especially
when compared with 2.

My experience in the past has been especially puzzling when I try to
combine atop with the MIDDLE TINE result of a fork as the following
examples attempt to cover. In these example I use at and atop in the names
to reflect the use of @ and @: ; I use app in the names to reflect the use
of append . These examples especially the comparison between the
application of meanatop and meanatopapp, clarify to me that atop uses the
rank of its predecessor (%

   mean i. 3 4
4 5 6 7
   meanat =: +/ #@% #
   meanat i. 3 4
1 1 1 1
   meanatop =: +/ #@:% #
   meanatop i. 3 4
4
   meanatapp =: +/ #@,@% #
   meanatapp i. 3 4
1 1 1 1
   meanatopapp =: +/ #@:,@% #
   meanatopapp i. 3 4
1 1 1 1
   meanatopappparen =: +/ #@(,@%) #
   meanatopappparen i. 3 4
1 1 1 1
   meanatappparen =: +/ #@:(,@%) #
   meanatappparen i. 3 4
4


On Fri, Jan 22, 2016 at 4:50 AM, Linda A Alvord <[email protected]>
wrote:
I think I finally understand the difference!

    A=:'a man a plan a canal'
   ;:A
┌─┬───┬─┬────┬─┬─────┐
│a│man│a│plan│a│canal│
└─┴───┴─┴────┴─┴─────┘
   f=: 13 :'#>;:y'
   g=: 13 :'#@>;:y'
   h=: 13 :'#@:>;:y'


-- 
(B=) <-----my sig
Brian Schott
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