Thanks Raul. I'm pleased you asked.

Originally, I couldn't see what you were trying to demonstrate. It's now
morning here, and having slept, I think I can see your point.

You're right. Sorry. My sentence wasn't entirely correct. You did assign
(and demonstrate) x =: 1 0 1$0 which indeed lacks any atoms.

I think I see my critical mistake. The x arguments in (1), (2), (3), (4)
have ranks 3, 3, 2, 1. My hasty application of (erroneous) intuition has
brought me unstuck: 0 atoms does not necessarily imply rank 0. I'll have
make a poster "rank = #$" and hang it on my wall.

On Sat, Feb 6, 2016 at 12:27 AM, Raul Miller <[email protected]> wrote:

> Why do you say "Your x arguments all have atoms so, I'm sorry, I can't
> see their significance."?
>
> What is different between the x values in my email message and the x
> values you originally specified?
>
> Thanks,
>
> --
> Raul
>
>
> On Fri, Feb 5, 2016 at 5:42 AM, Matthew Baulch <[email protected]>
> wrote:
> > The 'x $ y' dyad, like you say, has rank 1 for x and _ for y. Examples
> > (1)-(3) have rank 0 arguments for x. The x arguments are arrays with
> > non-empty shape but no atoms in these cases. Your x arguments all have
> > atoms so, I'm sorry, I can't see their significance. My x arguments have
> > shapes containing only non-negative integers (as you mentioned), although
> > some are zero. I'm not sure what you mean by:
> >
> > "So your first example is not even going to get to the reshape part of
> the
> > operation. Your frame, which will hold your results, is empty."
> >
> > I understand and agree that the frame of the left argument is empty. That
> > doesn't surprise or concern me. What I don't understand are the reasons
> for
> > the result shapes in (1)-(3), and why the result for (3) has an atom.
> >
> > All verbs (that I can think of) with an argument of rank >= 1 are defined
> > also for arguments of rank 0. For instance, 'i. y',  'x # y' (x has rank
> > 1), and so on. Of course, there are very many verbs having arguments of
> > infinite rank too. Therefore, I don't see it as remarkable to apply a
> rank
> > 0 array as an argument to a verb with rank > 0.
> >
> > Your comment
> >
> > "the dictionary definitions for verbs mostly only deal with arguments
> which
> > fit within the dictionary defined rank for the verb"
> >
> > was enlightening and made me think. Is it simply that the case that most
> > verb definitions don't cover the case of rank 0 arguments with no atoms?
> > Perhaps my question relates to an undefined part of J?
> >
> > On Fri, Feb 5, 2016 at 7:27 PM, Raul Miller <[email protected]>
> wrote:
> >
> >> I'm going to go with the original vocab definition, because that's how
> >> I understand reshape.
> >>
> >> But also keep in mind that the left rank of reshape is 1. A shape is a
> >> (usually quite short) list of non-negative integers. This is something
> >> that we all have to go through - remembering that the dictionary
> >> definitions for verbs mostly only deal with arguments which fit within
> >> the dictionary defined rank for the verb. That's good enough for most
> >> purposes, when you need to concern yourself with rank it's the same
> >> rules for all verbs (except for the actual numeric values being
> >> different on some verbs).
> >>
> >> Perhaps http://www.jsoftware.com/help/dictionary/dictb.htm would be
> >> worth reviewing?
> >>
> >> Anyways, to see what that means for your reshape examples, consider
> this:
> >>
> >>    <"1 x=: 1 0 1 $ 0
> >>
> >> (that's an empty result - no boxes.)
> >>
> >>    $<"1 x=: 1 0 1 $ 0
> >> 1 0
> >>
> >> (that's what your frame looks like, for this example.)
> >>
> >> So your first example is not even going to get to the reshape part of
> >> the operation. Your frame, which will hold your results, is empty.
> >>
> >> In your first example, x is empty, so you'll be using an array of
> >> fills (which are zeros) for the test run of reshape. So you actually
> >> do get a final dimension here - the last dimension is 1, and although
> >> x is empty, the interpreter uses that 1 to decide how many zeros it's
> >> going to use.
> >>
> >> Your second and third examples have the same issue  - you're not doing
> >> a single reshape but a collection of reshapes. But in those examples
> >> your last dimension of x is zero. So when the interpreter does its
> >> test run on the verb to see what kinds of results it's getting instead
> >> of doing:
> >>
> >>    (,0) $ 1 2 3
> >>
> >> like it was in the first example, it is instead doing
> >>
> >>    '' $ 1 2 3
> >> 1
> >>
> >> In other words there trial result doesn't have a shape, so you get one
> >> less dimension in your result than you had in x.
> >>
> >> As for your last example:
> >>
> >>    <"1 x=: 1 $ 0
> >> +-+
> >> |0|
> >> +-+
> >>    $ <"1 x=: 1 $ 0
> >>
> >> ...so your final example does do the reshaping, but you are reshaping
> >> with an empty shape, so you still get an empty result.
> >>
> >> Does this make sense?
> >>
> >> Thanks,
> >>
> >> --
> >> Raul
> >>
> >> On Fri, Feb 5, 2016 at 3:06 AM, Matthew Baulch <[email protected]>
> >> wrote:
> >> > Original vocab says:
> >> > "The shape of x$y is x,siy where siy is the shape of an item of y."
> >> >
> >> > NuVoc says (for x $ y):
> >> > "If y is an atom or a list, the shape of the result is x", and "the
> shape
> >> > of [the result of x$y] is always x,}.$y".
> >> >
> >> > Let y =: 1 2 3 for all that follows.
> >> >
> >> > (1)
> >> >    x =: 1 0 1 $ 0
> >> >    x$y has no atoms, shape 1 0 0
> >> > (2)
> >> >    x =: 1 0 0 $ 0
> >> >    x$y has no atoms, shape 1 0
> >> > (3)
> >> >    x =: 1 0 $ 0
> >> >    x$y has a single atom: 1, and shape 1
> >> > (4)
> >> >    x =: 1 $ 0
> >> >    x$y has no atoms, shape 0
> >> >
> >> > Examples (1)-(3) appear to violate the definitions. Only example (4)
> >> > agrees. Can anyone shed some light on this? (3) strikes me as
> >> particularly
> >> > strange. I'm sure I must have missed something.
> >> >
> >> > My head is spinning!
> >> > ----------------------------------------------------------------------
> >> > For information about J forums see
> http://www.jsoftware.com/forums.htm
> >> ----------------------------------------------------------------------
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