a1 =. ({.`)(`{:)(`:6)
erase'u'
1
u a1
{. u {:
eval=: 1 : ' a: 1 : m'
lrA =: 1 : '5!:5 < ''u'''
A =: 2 : ' (u lrA , '' '' , v) eval'
a1=. A '`{.`{:@.1 0 2'
erase'u'
1
u a1
|length error
| u`{.`{:@.1 0 2
'a1'f.
2 : ' (u lrA , '' '' , v) eval''`{.`{:@.1 0 2'
What this 2 : doing here? The use of illegal steroids is not appreciated
in this venue! :)
On Tue, Mar 15, 2016 at 9:31 PM, Pascal Jasmin <[email protected]>
wrote:
> spoiler alert... by placing answer at bottom
>
>
>
>
> ----- Original Message -----
> From: Jose Mario Quintana <[email protected]>
> To: Programming forum <[email protected]>
> Sent: Tuesday, March 15, 2016 6:32 PM
> Subject: Re: [Jprogramming] Adverbial Tacit Jym
>
> Right, so let us add a twist to the Exercise 1:
>
> Minor alert for anyone that have not seen Pascal's solution for a1...
>
> 7
> 6
> 5
> 4
> 3
> 2
> 1
> 0
>
> Produce a1 without involving @. in the code.
>
> Remember: "Spoiler alerts by instructors and patrons will be appreciated."
>
>
> On Mon, Mar 14, 2016 at 3:43 PM, <[email protected]> wrote:
>
> > Pascal Jasmin wrote:
> > > a0 =:
> > > a1 =:
> >
> > You are confusing the Jym with the Spoilarium, I'm afraid.
> >
> > Martin Neitzel
>
>
>
> a1 =. ({.`)(`{:)(`:6)
>
> I can see this as better than:
>
> a1 =. (`{.)(`{:)(@.1 0 2)
>
> but speaking of workarounds to apply adverbs correctly, here is one method
> that makes the above easier to write, and one way to workaround the syntax
> error discussed in other thread.
>
>
> eval=: 1 : ' a: 1 : m'
> lrA =: 1 : '5!:5 < ''u'''
> A =: 2 : ' (u lrA , '' '' , v) eval'
>
>
> + A '`{.`{:@.1 0 2'
>
>
> {. + {:
>
> or
>
> + A '({.`)`{:`:6'
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>
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