You nailed it.

   0.25p1 * i.5
0 0.785398 1.5708 2.35619 3.14159

Thanks,

-- 
Raul


On Thu, Apr 21, 2016 at 5:05 AM, Rob Hodgkinson <[email protected]> wrote:
> In your first case:
>    o. 4 %~ i.5
> 0 0.785398 1.5708 2.35619 3.14159
>    o. (i.5)%4   NB. Same as above ...
> 0 0.785398 1.5708 2.35619 3.14159
>    (o.i.5)%4    NB. Same again ...
> 0 0.785398 1.5708 2.35619 3.14159
>
> So the numerator is (o. * i. 5) and the denominator is 4
>
> In your last case:
>    4p1 %~ (i.5)
> 0 0.0795775 0.159155 0.238732 0.31831
>    (i.5) % 4p1  NB. Same as above ...
> 0 0.0795775 0.159155 0.238732 0.31831
>    (i.5) % o.4   NB. Same again ...
> 0 0.0795775 0.159155 0.238732 0.31831
>
> So the numerator is (i.5) and the denominator is o.4
>
> i.e. you have inadvertently moved the o. (or 4p1) to the denominator, likely 
> without realising
>
> Remember in your first example that o. is a verb, whose argument is the 
> result of  (4 %~ i.5).
>
> HTH …/Rob
>
>> On 21 Apr 2016, at 6:28 PM, Martin Kreuzer <[email protected]> wrote:
>>
>> Hi all -
>>
>> Somewhere along the way I picked up this small expression:
>>   o.4 %~ i.5
>> 0 0.785398 1.5708 2.35619 3.14159
>>
>> Just for the fun of it, I tried building it from the ground up like this:
>>   (i.5) % 4
>> 0 0.25 0.5 0.75 1
>>   1p1 * (i.5) % 4
>> 0 0.785398 1.5708 2.35619 3.14159
>>   1p1 * 4 %~ (i.5)
>> 0 0.785398 1.5708 2.35619 3.14159
>>
>> I then bravely thought this would work as well
>>   4p1 %~ (i.5)
>> 0 0.0795775 0.159155 0.238732 0.31831
>>   (4p1) %~ (i.5)
>> 0 0.0795775 0.159155 0.238732 0.31831
>> but -unfortunately- it didn't ...
>>
>> The "odot" page of NuVoc has given me the impression that the two should be 
>> interchangeable (despite maybe performance issues).
>>
>> Spoilers: A newbie at work.
>> -M
>>
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