Yes, that's because what is running is not a named definition. (It's 3 :
0 not t2)
In the jqt debugger I changed things so that if you set a stop in t2,
the debugger splits the definition into
t2compound =: original t2
t2 =: t2compound"0
and then puts the stop into t2compound. If you are using jqt you can
set a stop before running the program, to get a good stop.
If you are not running jqt I don't know what the best solution is. You
could split the definition by hand.
Or, maybe we could make up a name for the unnamed explicit definition,
and show that on the stack. That's a design change that would require
some thought and discussion.
Henry Rich
On 5/29/2016 10:12 AM, bill lam wrote:
Anther thing about debug stack is that it cannot show the correct
line number if the verb is defined by 3 : 0"n or n&$: : (4 : 0)
eg,
t1=: 3 : 0
1
t2''
4
)
t2=: 3 : 0"1
1
2
3
1+'a'
4
5
6
)
dbr 1
t1''
|domain error: t2
| 1 +'a'
dbctx''
@@ t2[0] *v @@ /home/bill/a1.ijs
3 : 0"1
[0] 1
[1] 2
[2] 3
[3] 1+'a'
dbstack''
+----+--+--+--+----+------+----+
|name|en|ln|nc|args|locals|susp|
+----+--+--+--+----+------+----+
|t2 |3 |0 |3 |++ | |* |
| | | | ||| | | |
| | | | |++ | | |
+----+--+--+--+----+------+----+
|t1 |0 |1 |3 |++ |+-++ | |
| | | | ||| ||y|| | |
| | | | |++ |+-++ | |
+----+--+--+--+----+------+----+
However it works if t1 and t2 are
t1=: 3 : 0
1
t2"1 ''
4
)
t2=: 3 : 0
1
2
3
1+'a'
4
5
6
)
dbr 1
t1''
|domain error: t2
| 1 +'a'
|t2[3]
dbstack''
+----+--+--+--+----+------+----+
|name|en|ln|nc|args|locals|susp|
+----+--+--+--+----+------+----+
|t2 |3 |3 |3 |++ |+-++ |* |
| | | | ||| ||y|| | |
| | | | |++ |+-++ | |
+----+--+--+--+----+------+----+
|t1 |0 |1 |3 |++ |+-++ | |
| | | | ||| ||y|| | |
| | | | |++ |+-++ | |
+----+--+--+--+----+------+----+
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