I was just wondering if 1 2 4 6 5 3 2 1 is considered a cycle since 2 is
traversed twice. I would think not.

Louis

> On 25 Aug 2016, at 13:42, R.E. Boss <[email protected]> wrote:
> 
> It's not a directed cycle
> 
>   (1+i.26) /:~"1|: ({.,#)/.~ , edges
> 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
> 2 2 2 2 2 2 2 2 2  2  2  2  2  2  2  2  2  2  2  2  2  2  2  2  2  2
> 
> R.E. Boss
> 
> 
>> -----Original Message-----
>> From: Programming [mailto:[email protected]]
>> On Behalf Of Raul Miller
>> Sent: donderdag 25 augustus 2016 13:23
>> To: Programming forum <[email protected]>
>> Subject: Re: [Jprogramming] determine the cycle
>> 
>> That is not a cycle.
>> 
>>   (1+i.26) -. {."1 edges
>> 8 19 24
>> 
>> --
>> Raul
>> 
>> 
>> On Thu, Aug 25, 2016 at 6:13 AM, R.E. Boss <[email protected]> wrote:
>>> Given the edges in a graph which is a cycle, like
>>>   edges
>>> 1  2
>>> 3  1
>>> 2  4
>>> 4  5
>>> 5  6
>>> 6  7
>>> 7  8
>>> 9  8
>>> 10  9
>>> 11 10
>>> 11 12
>>> 12 13
>>> 14 15
>>> 15 16
>>> 17  3
>>> 18 17
>>> 18 19
>>> 20 19
>>> 20 21
>>> 21 22
>>> 22 14
>>> 16 23
>>> 13 24
>>> 25 24
>>> 26 25
>>> 23 26
>>> Vertices of the graph are represented by >:i.26
>>> Question is how to determine in an elegant way the sequence of vertices
>> along the cycle, which is
>>> 1 2 4 5 6 7 8 9 10 11 12 13 24 25 26 23 16 15 14 22 21 20 19 18 17 3 1
>>> 
>>> 
>>> R.E. Boss
>>> 
>>> 
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