d is there - it's the result of <: and right argument to the fork.
The problem is that (a a d) produces ([: a a) instead of ([: a a@]) .
I have no interest in working on 13 : but if someone else wants to I can
offer guidance through the rest of the interpreter.
Henry Rich
On 12/27/2016 7:05 PM, 'Pascal Jasmin' via Programming wrote:
d is a noun in 3 :
it does not appear in result of 13
13 : is buggy. The tacit version you want is
a =: (a@:a@:<: + ] a@:([ - a@]) <:)`1:@.(<:&2)
----- Original Message -----
From: Louis de Forcrand <[email protected]>
To: [email protected]
Sent: Tuesday, December 27, 2016 6:07 PM
Subject: [Jprogramming] Strange 13 : '...' behavior
From: http://rosettacode.org/wiki/Hofstadter-Conway_$10,000_sequence
<http://rosettacode.org/wiki/Hofstadter-Conway_$10,000_sequence>
JVERSION
Engine: j805/j64/darwin
Beta-12: commercial/2016-09-30T16:11:35
Library: 8.05.07
Platform: Darwin 64
Installer: J805 install
InstallPath: /users/louisdeforcrand/applications/j64-805
Contact: www.jsoftware.com
a=: 3 : '(a a d)+a y-a d=.<:y'`1:@.(<:&2)
a"0>:i.10 NB. correct behavior
1 1 2 2 3 4 4 4 5 6
a=: 13 : '(a a d)+a y-a d=.<:y'`1:@.(<:&2)
a"0>:i.10 NB. incorrect behavior
1 1 2 3 4 5 6 7 8 9
a
(] (([: a a) + [: a [ - a) <:)`1:@.(<:&2)
Anybody know what’s going on?
Louis
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