2nd example,
-&# keyD~ 1 2 3 1 3 2 1 4 5 5 dyadic & here. keyD called with ~ so x and y are the same. u is -&# . the x to u is y of the whole function. (# x) - # y. 7 constant to each call for x, and the count of each key is 3 2 2 ----- Original Message ----- From: Brian Schott <[email protected]> To: Programming forum <[email protected]> Sent: Friday, January 13, 2017 11:14 PM Subject: Re: [Jprogramming] dyadic key Pascal, I don't understand your second example at all. I finally understand the first example after noticing the following result, I realize the result of keyD produces the indices of adg,bf,ce in abcdefg. 1 2 3 1 3 2 1 </. 'abcdefg' +---+--+--+ |adg|bf|ce| +---+--+--+ But what is going on in the second example. ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
