Jon, I haven't been using J for a while so I tried your problem. In a way I
must think like a beginner again. Here's my take after a false start where I
used APL!
[A=:?6#50
40 5 19 46 34 40
>/A
1
>./A
46
i.$A
0 1 2 3 4 5
A=>./A
0 0 0 1 0 0
i.$A
0 1 2 3 4 5
(A=>./A) #i.$A
3
f=: 13 :'(y=>./y)#i.$y'
f A
3
f
(] = >./) # [: i. $
So this is "beginner Tacsit" that seems to work. Then it is fun to see what I
can learn from the masters who have already solved your problem. Keep sending
your questions. They are goo for all of us.
Linda
-----Original Message-----
From: Programming [mailto:[email protected]] On Behalf
Of 'Jon Hough' via Programming
Sent: Tuesday, January 24, 2017 11:29 PM
To: [email protected]
Subject: Re: [Jprogramming] Return of max of list and it's index in single pass
Yep, that's what I was looking for. Thanks!
--------------------------------------------
On Wed, 1/25/17, Raul Miller <[email protected]> wrote:
Subject: Re: [Jprogramming] Return of max of list and it's index in single
pass
To: "Programming forum" <[email protected]>
Date: Wednesday, January 25, 2017, 12:01 PM
maxIndexAndValue=:
((i.,]) >./)
I hope this
helps,
--
Raul
On Tue, Jan 24, 2017 at 9:58 PM, 'Jon
Hough' via Programming
<[email protected]>
wrote:
> I want to get the max value of a
list, and return the first index of its occurrence in the list, tacitly.
>
> My
solution
>
>
maxWithIndex =: {.@:I.@:(= >./), >./
>
> works ok, but
calculates >./ twice. Is there a tacit way to do this with only a single calc
of >./ ?
>
> Thanks,
> Jon
>
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