Here's my take on what I think you are asking for:
10&#.inv 41 35
4 1
3 5
+//. 10&#.inv |.41 35
3 9 1
2 {. +//. 10&#.inv |.41 35
3 9
(2 {. +//.)&. (10&#.inv) |.41 35
39
carry=: (2 {. +//.)&. (10&#.inv)@|.
T=: 6 6 $ 3 7 1 0 7 9 4 6 3 7 6 9 7 4 3 2 4 9 9 1 9 4 2 2 2 3 0 6 7 5
+/ |. "1 T
43 33 19 17 28 28
S=: +/ |. "1 T
carry/ L:0 < \ S
┌──┬──┬──┬──┬──┬──┐
│43│33│19│17│28│28│
└──┴──┴──┴──┴──┴──┘
carry/\ S
43 33 19 17 28 28
Whether this relates to PE 13 or not, I am not sure.
But I hope some of this might help.
Thanks,
--
Raul
On Mon, May 22, 2017 at 5:50 AM, Lafras Uys <lafr...@gmail.com> wrote:
> Hi,
>
> I am working through Project Euler to learn J. For PE 13 I am trying to
> implement a carry function. For example:
>
> 41 carry 35 = 39 NB. Add the tens from 41 to the ones of 35
>
> This is what I have so far:
>
> NB. "Large" numbers
>
> ] T=: 6 6 $ 3 7 1 0 7 9 4 6 3 7 6 9 7 4 3 2 4 9 9 1 9 4 2 2 2 3 0 6 7 5
> 8 9 2 6 9 7
>
> 3 7 1 0 7 9
>
> 4 6 3 7 6 9
>
> 7 4 3 2 4 9
>
> 9 1 9 4 2 2
>
> 2 3 0 6 7 5
>
> 8 9 2 6 9 7
>
> < \ S=: +/ |. "1 T NB. Suffixes of the reversed radix sums
>
> +--+-----+--------+-----------+--------------+-----------------+
>
> |41|41 35|41 35 25|41 35 25 18|41 35 25 18 30|41 35 25 18 30 33|
>
> +--+-----+--------+-----------+--------------+-----------------+
>
> f=: (0&{ @: ((0 10) & #:)) @: [ NB. Grab the number of tens in x
>
> g=: +
>
> h=: ]
>
> carry=: (f g h)
>
> carry/ L:0 < \ S
>
> +--+--+--+--+--+--+
>
> |41|39|32|27|40|46|
>
> +--+--+--+--+--+--+
>
>
> My carry verb works fine for the first two numbers, however as soon as
> there are three or more numbers it looks like all the "tens" from x is
> added to y, e.g. 4+3+25 = 32 instead of 28. My understanding is that `/`
> acts like a fold, maintaining an accumulator as in +/ 2 3 4 5 = (((2+3) +
> 4) + 5) so that the left hand side is the result of the computation to
> date. I'm clearly missing something important here.
>
>
> Any comments and help is appreciated,
>
>
> Lafras
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