For a 0,1,2,3 4,...n representation of the board, I take it?

Thanks.

Michael

On Tue, Jun 6, 2017 at 10:18 AM, Henry Rich <[email protected]> wrote:

> I use
>
> setintersect =: e. # [
>
> Henry Rich
>
>
> On 6/6/2017 6:11 AM, 'Mike Day' via Programming wrote:
>
>> My point being,  if Michael Rice is exploring how to solve peg solitaire,
>> it's often useful to work on small(er) problems, before perhaps getting
>> stuck in a long loop,  or seeing the memory climb and one's pc seize up
>> and need rebooting.
>>
>> But he'll know all this stuff anyway!
>>
>> BTW, re Raul's useful thoughts on union matters, same thread, earlier
>> post.
>> I've just noticed that the intersection I posted,  ix = [-.-. , is,
>> perhaps, "lazy";
>> better might be ~.@([-.-.),  but neither is appropriate for bit-vector
>> comparisons!
>>
>> Cheers,
>> Mike
>>
>>
>> On 06/06/2017 10:28, Raul Miller wrote:
>>
>>> On Tue, Jun 6, 2017 at 4:09 AM, 'Mike Day' via Programming
>>> <[email protected]> wrote:
>>>
>>>> if I were developing a solver for solitaire,  I'd include a variable as
>>>> a
>>>> parameter for
>>>>
>>>> the size of problem,  eg the number of rows,  1 2 3 etc,  or the
>>>> ravel-size,
>>>> eg 1 3 6 etc.
>>>>
>>> You had not specified that previously, but note that implementing this
>>> is a simple change.
>>>
>>> For example:
>>>
>>> flip=: [ ~: i.@#@[ e. ]
>>>
>>> solitaire=:3 :0
>>>    5 solitaire y
>>> :
>>>    path=. (y flip~ 1#~ 0 0.5 0.5 p. x) search i.0 3
>>>    if. #path do. path else. 'No solution' end.
>>> )
>>>
>>> That said, the 'No solution' cases require a time-consuming exhaustive
>>> search, and in the few tests I did with sizes other than 5, I was
>>> hitting no solution cases. It's time consuming because each
>>> permutation of moves that leads to a final board state gets tested.
>>>
>>> Still, I hope this helps,
>>>
>>>
>>
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