I've only just seen this. I expect it's obvious, but you ARE looking only for rectangles with "vertical" and "horizontal" sides, i.e. no rotations other than multiples of pi/2 involved? Thanks, Mike
Please reply to mike_liz....@tiscali.co.uk. Sent from my iPad > On 20 Jun 2017, at 16:29, Raul Miller <rauldmil...@gmail.com> wrote: > > Something I stumbled over today. > > If we have a series of bars of varying height, what's the largest > rectangle that can be drawn over the bars without covering any empty > space. > > For example: > > '*'#"0~2 6 7 4 1 7 > ** > ****** > ******* > **** > * > ******* > > I'll post a solution later, and I'll be interested in seeing if it's > basically the only obvious approach or if there's a variety of good > approaches. (I have reason to believe, though, that there's a better > way than what I came up with.) > > Thanks, > > -- > Raul > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm