Hi,

problem is with 4 5 6 which denote the following:

   coh=: 4&o.        NB. sqrt (1+(y^2))
   sinh=: 5&o.       NB. hyperbolic sine of y
   cosh=: 6&o.       NB. hyperbolic cosine of y

see: http://code.jsoftware.com/wiki/Vocabulary/odot#dyadic

There dosen't seem to be specific numbers for cot, sec and csc.
You have to go by their definition:

[image: \cot \theta ={\frac {\cos \theta }{\sin \theta }}=\tan \left({\frac
{\pi }{2}}-\theta \right)={\frac {1}{\tan \theta }}]

[image: \sec \theta =\csc \left({\frac {\pi }{2}}-\theta \right)={\frac
{1}{\cos \theta }}]

[image: \csc \theta =\sec \left({\frac {\pi }{2}}-\theta \right)={\frac
{1}{\sin \theta }}]



On Tue, Aug 15, 2017 at 12:41 PM, Linda Alvord <[email protected]>
wrote:

>
>
> Sent from AOL Mobile Mail
>
>
> From: Linda Alvord <[email protected]>
> Date: Tuesday, August 15, 2017
> Subject: FW: why are there no negative signs for cot,sec and csc?
> Cc: lindaalvord <[email protected]>
>
> 
> ​​
>
>
>
>
>
>
> From: Linda Alvord [mailto:[email protected]]
> Sent: Tuesday, August 15, 2017 11:22 AM
> To: '[email protected]' <[email protected]>
> Subject: why are there no negative signs for cot,sec and csc?
>
>
>
> do=: 13 : '({.y) +(i.{:y)*(--/ 2{.y)%<:{:y'
>
> t=:do 0 2p1 17
>
> all=:1 2 3 4 5 6 (o."0 1) t
>
> *all
>
> 0 1 1 1 1 1 1 1 0 _1 _1 _1 _1 _1 _1 _1 0
>
> 1 1 1 1 0 _1 _1 _1 _1 _1 _1 _1 0 1 1 1 1
>
> 0 1 1 1 1 _1 _1 _1 0 1 1 1 1 _1 _1 _1 0
>
> 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
>
> 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
>
> 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
>
>
>
> Linda
>
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