It loses accuracy somewhere between n=150 and n=200.

Keep in mind though that the dimensions of these "volumes" are not comparable.

Each "n-volume" of dimension n-1 is "paper thin (or thinner)" than the
"n-volume" of dimension n.

That said, I have not sat down and verified the results by hand, I'm
just trusting that the equation is accurate (though it seems to be).

See also: https://en.wikipedia.org/wiki/Volume_of_an_n-ball

Thanks,

-- 
Raul

On Tue, Aug 15, 2017 at 4:18 PM, Jan-Pieter Jacobs
<[email protected]> wrote:
> Nice sentence.
>
> Is it accurate for higher dimensions too? To me it seems a bit
> counterintuitive that after n=6, the n-volume rapidly declines until almost
> zero.
>
> For instance:
> load 'plot'
> plot 1 sphvol i. 100
>
> Best regards,
>
> Jan-Pieter
>
> On 15 Aug 2017 7:55 p.m., "Raul Miller" <[email protected]> wrote:
>
>>    sphvol=: (1p1&^%!)@-:@] * ^
>>    1 sphvol 3
>> 4.18879
>>    1 sphvol i.7
>> 1 2 3.14159 4.18879 4.9348 5.26379 5.16771
>>
>> Left argument is the radius of the "n-sphere".
>>
>> Right argument is the number of dimensions.
>>
>> I put "n-volume" in quotes, because if the dimension is 2 (for
>> example), the "n-volume" is what we call the area of the circle. (And
>> if the dimension is 1 that "n-volume" is the length of a line
>> segment).
>>
>> Anyways, I stumbled across this and thought it might be interesting
>> for someone else.
>>
>> Thanks,
>>
>> --
>> Raul
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