I'd have done this: 0 12 16#:16*166.7 13 10 11.2
13' 10" and slightly over 11/16. Similar to Xiao-Yong's approach, though slightly different. Thanks, -- Raul On Mon, Sep 18, 2017 at 1:10 PM, Brian Schott <[email protected]> wrote: > My car is 166.7 inches long according to the specs. > Car cover coverages are measured in feet and inches. > > To compute how many feet and inches long my car is I used the following > calculations. > > 166.7%12 > 13.8917 > (-<.)166.7%12 > 0.891667 > 12x *(-<.)166.7%12 NB. the x is not required, imo > 10.7 > > Which seems to suggest the car is 13 feet 10.7 inches long, right? > > Being a little annoyed at how difficult that calculation seems I decided to > try to also see how many 16ths of an inch is added, so I did the following > which seems to suggest between 11 and 12 sixteenths. > > 16x * (-<.) 12x *(-<.)166.7%12 NB. again, x is extra > 11.2 > > I wonder if there is an easier way to do this, which in my recollection > seems to be in the wheelhouse of Ian's Tabula or its brethren. I had > expected #: to be involved in the calculations, but could not find such. > > > -- > (B=) > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
