Here is another way:

   4 4.5 0.5 p. i.10
4 9 15 22 30 39 49 60 72 85

On Fri, Sep 29, 2017 at 3:32 AM, 'Mike Day' via Programming <
[email protected]> wrote:

> Linda offers:
> f=: 13 :'+/"1(>:/~i.y)*(y#x)+/i.y' NB. (msgsbelow)
>
> My best f ,  with an [: for Linda's sake:
>    f =: ([:+/\ (+i.))
>    4 f 7
> 4 9 15 22 30 39 49
>
> HOWEVER, although Skip initially asked for a way to render
> 4, (4+5), (4+5+6),  ... recursively, we may consider that
> the (i+1)th term may be defined recursively as
>    t(i+1) = ti + 4 + i,  t0 = 4,
> and it's easy to see that ti = 4i + i(i-1)%2
>
> So, IF the requirement were just to obtain the nth term
> in (a f n), we can predict the term using triangular numbers,
> 2!]  (or -:*<:) :
>    fn =: * + 2!] NB. does nicely
>    4 fn 7
> 49
>    4 fn >:i.7     NB. it can generate the whole sequence
> 4 9 15 22 30 39 49
>
> (Note, however,  fa =: fn (>:@i.) performs worse than f !)
>
> It comes into its own for long sequences:
>    <.4 fn 7000000
> 24500024500000
>    <.4 {:@f 7000000   NB. also last element of f
> 24500024500000
> ts '<.4 fn 7000000'
> 7.01939e_6 1664
> ts '<.4 {:@f 7000000'  NB. slower and muchgreedier
> 0.243402 1.34219e8
>    Note, however,
>    ts '<.4 {:@fa 7000000'NB. as I said!
>
> 1.01148 2.01328e8
>
>
> Any use?
> Mike
>
> On 29/09/2017 02:57, Linda Alvord wrote:
>
>> Or:
>> f=: 13 :'+/"1(>:/~i.y)*(y#x)+/i.y'
>>     4 f 7
>> 4 9 15 22 30 39 49
>>    Linda
>>
>> Sent from AOL Mobile Mail
>>
>> On Thursday, September 28, 2017 Raul Miller <[email protected]>
>> wrote:
>> Nothing is simpler than the i. approach, but ^: is not significantly more
>> complex than $: approach: }:(}:,+/@(_2&{.),>:@{:)^:9]4 4 9 15 22 30 39 49
>> 60 72 Thanks, -- Raul
>>
>> On Thu, Sep 28, 2017 at 3:37 PM, Xiao-Yong Jin <[email protected]>
>> wrote: > > >> On Sep 28, 2017, at 1:40 PM, Raul Miller <
>> [email protected]> wrote: >> >> That is what I would assume: >> >>
>> 4,(4+5),(4+5+6),(4+5+6+7),(4+5+6+7+8) >> 4 9 15 22 30 >> >> I was trying
>> to figure out a recursive approach which isn't vastly >> more tedious... >
>> > 4( [, +( ([,+)`$:@.(10>]) ) >:@])5 > > On the other hand, ^: can be used,
>> but I don't see any simpler. > >> >> Thanks, >> >> -- >> Raul >> >> >> On
>> Thu, Sep 28, 2017 at 2:39 PM, Roger Hui <[email protected]>
>> wrote: >>> You don't mean >>> >>> +/\4+i.10 >>> 4 9 15 22 30 39 49 60 72 85
>> >>> >>> do you? >>> >>> >>> >>> On Thu, Sep 28, 2017 at 11:33 AM, Skip Cave
>> <[email protected]> wrote: >>> >>>> What is a good way to generate
>> this sequence in J? >>>> >>>> 4,(4+5),(4+5+6),(4+5+6+7),(4+5+6+7+8)+.....
>> >>>> >>>> Show one way using i. and insert. >>>> >>>> Show another way
>> using recursion. >>>> >>>> Skip >>>> >>>> Skip Cave >>>> Cave Consulting
>> LLC >>>> 
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