Wow - more than I could manage with my phone and phingers!
Or desktop! So have we got closed forms for k=3, k=n-2? M On 23/11/2017 02:49, Raul Miller wrote:
Hmm... right - it corresponds to an upper (or lower) triangular matrix, not the identity matrix. So... (|.>:/~i.x)#&(,/)(i.x)+(1 j.(i.x)=/-~/~i.x)#"1"_1-~/~i.x In other words, once again, oops. (But at least, this time, I tested the expression. Though I know it could be refactored to be more concise-- but the phone UI is too clumsy for that...) Thanks,
--- This email has been checked for viruses by Avast antivirus software. https://www.avast.com/antivirus ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
