Please elaborate on what confused you in that article. [May I say, if
you want to learn about x u/ y, there's much more information on the
page for that primitive rather than the page for {y ].
The inner verb rank of u/ DOES matter. It's crucial. Please read the
page on x u/ y and then tell me if you still think the docs need more work.
Henry Rich
On 12/2/2017 3:07 PM, Joe Bogner wrote:
Thanks Henry & Raul - I figured it was rank but couldn't figure out why. I
guess I assumed it would somehow use the rank of the tines.
This NuVoc article is what tripped me up -
http://code.jsoftware.com/wiki/Vocabulary/curlylf
Specifically this example got me thinking that the 'inner' verb rank
mattered, but it was just my misread of the parentheses (there is no inner
verb!)
0 1 (<@,"0)/ 7 8 9
vs
0 1 (<@,)"0/ 7 8 9
vs
0 1 <@,"0/ 7 8 9
all are the same, but it doesn't mean that placing rank inside the verb for
the / adverb matters. Sharing in case it helps someone else...
Thanks again
On Sat, Dec 2, 2017 at 2:39 PM, Henry Rich <[email protected]> wrote:
Rank.
(~: *. (0&= @ |~)) b. 0
_ _ _
(0&= @ |~) b. 0
_ 0 0
~: b. 0
_ 0 0
Henry Rich
On 12/2/2017 2:34 PM, Joe Bogner wrote:
I was working on my adventofcode solution earlier today and was stuck and
still can't figure out why this doesn't work.
Take this expression.
(0&= @ |~)/~ 5 9 2 8
1 0 0 0
0 1 0 0
0 0 1 0
0 0 1 1
And this expression
(~:)/~ 5 9 2 8
0 1 1 1
1 0 1 1
1 1 0 1
1 1 1 0
Why can't I combine it into a single fork to AND the two tines?
(~: *. (0&= @ |~))/~ 5 9 2 8
0 0 0 0
Instead I have to do this
(~:/~ *. (0&= @ |~)/~) 5 9 2 8
0 0 0 0
0 0 0 0
0 0 0 0
0 0 1 0
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