The rank of monadic i. is 1 as determined by the following. i. b. 0 1 _ _
Consider the following where the rows and column lengths of i. 1 2 are made to match those of i. 3 4. (i. 1 2),:i. 3 4 0 1 0 0 0 0 0 0 0 0 0 0 0 1 2 3 4 5 6 7 8 9 10 11 But that may not be explanation enough. On Tue, Dec 12, 2017 at 5:49 PM, TongKe Xue <[email protected]> wrote: > Hi, > > > I understand what (2 2 $ 1 2 3 4) does. > I understand what i. 1 2 does > I understand what i. 3 4 does. > > I have read http://www.jsoftware.com/help/jforc/loopless_code_i_verbs_ > have_r.htm#_Toc191734331 > > I understand the concept of verb-rank, of frames + cells, of > "promoting one frame to another if they share the same prefix." > > I don't understand how the 0 padding in > > i. (2 2 $ 1 2 3 4) works > > > What is the mechanism by which 0-padding is happening? > > > Thanks, > --TongKe > > > ==== > > 2 2 $ 1 2 3 4 > > 1 2 > > 3 4 > > i. 1 2 > > 0 1 > > i. 3 4 > > 0 1 2 3 > > 4 5 6 7 > > 8 9 10 11 > > i. (2 2 $ 1 2 3 4) > > 0 1 0 0 > > 0 0 0 0 > > 0 0 0 0 > > > 0 1 2 3 > > 4 5 6 7 > > 8 9 10 11 > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm -- (B=) <-----my sig Brian Schott ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
