I confirm that on the 806 release linux that:
   0x1
2.7128

On Sat, Dec 16, 2017 at 12:37 PM, Henry Rich <[email protected]> wrote:

> 0x1
>
> 0
>
>    9!:14''
>
> j806/j64/windows/release/commercial/www.jsoftware.com/2017-11-06T10:03:54
>
>
> Something Linux-related?
>
>
> Henry Rich
>
>
>
>
> On 12/16/2017 12:31 PM, J. Patrick Harrington wrote:
>
>> 0x1
>> 2.71828
>>    9!:14''
>> j806/j64/linux/release/commercial/www.jsoftware.com/2017-11-06T09:54:01
>>
>> and same result on the nonavx version of 806 on my mac.
>>
>> On Sat, 16 Dec 2017, Henry Rich wrote:
>>
>>> When I try it (on a couple of different J versions) I get
>>>    0x1
>>> 0
>>>    0x0
>>> 0
>>> etc.
>>>
>>> If your error persists please run
>>>    9!:14''
>>>
>>> to indicate what version you are running, and report the error again.
>>>
>>> Welcome to J!
>>>
>>> Henry Rich
>>>
>>> On 12/16/2017 6:19 AM, [email protected] wrote:
>>>
>>>>  Hi.
>>>>
>>>>  Could someone please shed some light on the following behavior:
>>>>
>>>>      1p1
>>>>  3.14159
>>>>      0p1
>>>>  0
>>>>      0p0
>>>>  0
>>>>      1x1
>>>>  2.71828
>>>>      0x1
>>>>  2.71828
>>>>      0x0
>>>>  0
>>>>
>>>>  I don't understand why 0x1 isn't the same as 0 * ^1 even though
>>>>  other constants seem to obey this form. I haven't found any
>>>>  explanation in
>>>>  http://www.jsoftware.com/docs/help806/dictionary/dcons.htm .
>>>>
>>>>  <information irrelevant to the question>
>>>>
>>>>  I am new to J and am yet to write a useful script in it, but
>>>>  I've already been greatly impressed by how consistent the
>>>>  language felt in most cases. For example, just the other day
>>>>  I wrote a monadic verb which took $n$ as an argument and
>>>>  returned $\sum_k {n \choose 3k}$. The verb was the following:
>>>>
>>>>       a =: [:+/(3*i.)!]
>>>>
>>>>  But if you try to pass it not a single $n$ but a list, the
>>>>  verb doesn't work. Which is a shame because the intended use
>>>>  was to examine the series. And so I started searching for
>>>>  something akin to Haskell's `map`. After half an hour of
>>>>  sifting through J tutorials that expressed delight in the
>>>>  fact that J lifts operations to arrays of arbitrary ranks
>>>>  by default and therefore doesn't need `map`, I've finally
>>>>  found what I was looking for, namely `a "0 i.50`, the rank
>>>>  operator, and it turned out that `map` isn't magic after
>>>>  all and is just a single case of a more general operation.
>>>>  I hadn't seen the rank operator in any language before and
>>>>  was thrilled to feel the potential that this operator holds.
>>>>
>>>>  So the language is great, and it seems that common use cases
>>>>  are handled by elegant general solutions, that is, the
>>>>  language is designed to be mostly free from corner cases.
>>>>
>>>>  That's why the unintuitive handling of 0x1 seems to me
>>>>  especially weird. I could ignore it if Python did it, if
>>>>  C++ did it, but J simply doesn't look like a language that
>>>>  intoduces inconsistencies for no reason. So it is highly
>>>>  probable that it's me who doesn't understand higher purpose
>>>>  of the construct. And so I came here hoping that someone
>>>>  explains it to me. The J community has a reputation of
>>>>  being tolerant to uninsightful questions of beginners.
>>>>
>>>>  </information irrelevant to the question>
>>>>
>>>>  Sorry if my English has some mistakes or is in the wrong
>>>>  tone. The reason isn't negligence, it's just that English
>>>>  isn't my native language.
>>>>
>>>>  Regards,
>>>>  Dmitry Khalansky.
>>>>  ----------------------------------------------------------------------
>>>>  For information about J forums see http://www.jsoftware.com/forums.htm
>>>>
>>>
>>>
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