My version g causes domain error,
is, but is group correct?

y=:'ABCDEFGHIJKLMN'
   0.5 0.25 0.25 group y
┌────────┬───┬───┐
│ABCDEFGH│IJK│LMN│
└────────┴───┴───┘

So I tried this and it doesn't look good either.

0.5 0.25 0.25 group i.14
┌───────────────┬──────┬────────┐
│0 1 2 3 4 5 6 7│8 9 10│11 12 13│
└───────────────┴──────┴────────┘

Linda

-----Original Message-----
From: Programming [mailto:[email protected]] On Behalf 
Of Ric Sherlock
Sent: Sunday, December 17, 2017 12:48 AM
To: Programming JForum <[email protected]>
Subject: Re: [Jprogramming] Splitting an Array into several arrays

Hi Raul,
You're right. Writing emails on a phone is not something that comes naturally 
to me, so my responses tend to be pretty brief.
Cheers
Ric

On 16/12/2017 18:18, "Raul Miller" <[email protected]> wrote:

> When you say things like this, it's good to provide an example of what 
> you're talking about.
>
> Perhaps:
>
>    0.35 0.3 0.3 group2 'ABCDEFGHIJKLMN'
> ┌─────┬─────┬────┐
> │ABCDE│FGHIJ│KLMN│
> └─────┴─────┴────┘
>    0.35 0.3 0.3 f 'ABCDEFGHIJKLMN'
> |domain error: f
>
> Thanks,
>
> --
> Raul
>
>
> On Sat, Dec 16, 2017 at 12:14 AM, Ric Sherlock <[email protected]> wrote:
> > Note that group2 and f are not equivalent.
> >
> > On 16/12/2017 00:05, "Linda Alvord" <[email protected]> wrote:
> >
> >> Ric,
> >>
> >> Here's a response to an old thread which I took from my "things to 
> >> think about collection:
> >>
> >> group2=:(+/\@(* #) I. i.@#@]) </. ]
> >>    0.35 0.3 0.3 group2 i.14
> >> ┌─────────┬─────────┬───────────┐
> >> │0 1 2 3 4│5 6 7 8 9│10 11 12 13│
> >> └─────────┴─────────┴───────────┘
> >>    f=: 13 : '(x (] I.~ [: +/\ [ * [: # ]) y)</. y'
> >>    0.35 0.3 0.3 f i.14
> >> ┌─────────┬─────────┬───────────┐
> >> │0 1 2 3 4│5 6 7 8 9│10 11 12 13│
> >> └─────────┴─────────┴───────────┘
> >>
> >>    group2
> >> (+/\@(* #) I. i.@#@]) </. ]
> >>    f
> >> ] </.~ ] I.~ [: +/\ [ * [: # ]
> >>
> >> I was surprised at how neat f turned out when I wrote an explicit 
> >> definition of my version of you way to group the numbers.
> >>
> >> Linda
> >>
> >>
> >> -----Original Message-----
> >> From: Programming [mailto:[email protected]] 
> >> On Behalf Of Ric Sherlock
> >> Sent: Saturday, October 21, 2017 3:21 PM
> >> To: Programming JForum <[email protected]>
> >> Subject: Re: [Jprogramming] Splitting an Array into several arrays
> >>
> >> Jon,
> >> The following assigns each of the data points to a group, then 
> >> boxes
> those
> >> groups using key.
> >>
> >>    assignGrp=: +/\@(* #) I. i.@#@]
> >>    group=: assignGrp </. ]
> >>    0.35 0.35 0.3 group i.14
> >> ┌─────────┬─────────┬───────────┐
> >> │0 1 2 3 4│5 6 7 8 9│10 11 12 13│
> >> └─────────┴─────────┴───────────┘
> >>
> >> On 21/10/2017 02:14, "'Jon Hough' via Programming" < 
> >> [email protected]> wrote:
> >>
> >> > Hi,
> >> >
> >> > What I am really after is a verb that splits by percentage. To 
> >> > give a concrete uses case:
> >> > I have a dataset, which I wish to split into training set, 
> >> > validation set, and testing set.
> >> >
> >> > I want 35% of the datapoints to go in the training set, 35% go in 
> >> > the validation set, the rest go in the test set. (Just example numbers).
> >> >
> >> >
> >> > No need to worry about shuffling, randomizing etc, I am assuming 
> >> > the data is sufficiently random.
> >> > As Raul said, I can simplify slightly by just using the size of 
> >> > the dataset as the right argument.
> >> >
> >> > --------------------------------------------
> >> > On Fri, 10/20/17, Erling Hellenäs <[email protected]> wrote:
> >> >
> >> >  Subject: Re: [Jprogramming] Splitting an Array into several 
> >> > arrays
> >> >  To: [email protected]
> >> >  Date: Friday, October 20, 2017, 10:06 PM
> >> >
> >> >  Hi all !
> >> >
> >> >  A splitSubs with CutN could possibly look like
> >> >  this:
> >> >
> >> >  splitSubsE=: ([ (([:
> >> >  # [) {. ]) ([: <. 0.5 + [: }: [ * [: # ]) ( [ , ([:
> >> >  # ]) - [: +/ [) ]) CutN ]
> >> >
> >> >      (i.0) splitSubsE i.0
> >> >
> >> >      (,55) splitSubsE ,5
> >> >  ┌─┐
> >> >  │5│
> >> >  └─┘
> >> >      split
> >> >  splitSubsE i.0
> >> >  ┌┬┬┐
> >> >  ││││
> >> >  └┴┴┘
> >> >      split splitSubsE i.1
> >> >  ┌┬┬─┐
> >> >  │││0│
> >> >  └┴┴─┘
> >> >      split
> >> >  splitSubsE i.2
> >> >  ┌─┬─┬┐
> >> >  │0│1││
> >> >  └─┴─┴┘
> >> >      split
> >> >  splitSubsE i.3
> >> >  ┌─┬─┬─┐
> >> >  │0│1│2│
> >> >  └─┴─┴─┘
> >> >
> >> >  split splitSubsE i.4
> >> >  ┌─┬─┬───┐
> >> >  │0│1│2 3│
> >> >  └─┴─┴───┘
> >> >
> >> >  Cheers
> >> >
> >> >  Erling
> >> >  Hellenäs
> >> >
> >> >
> >> >  Den 2017-10-20 kl. 14:11, skrev Erling
> >> >  Hellenäs:
> >> >  > Hi all!
> >> >  >
> >> >  > I looked for a
> >> >  version of Cut which takes the number of items in each  > group 
> >> > as left argument. I didn't find  one. I think it is what you most  
> >> > > often  need, because it allows groups with zero length content.
> >> >  >
> >> >  > I made CutN as an
> >> >  illustration:
> >> >  >
> >> >  >
> >> >  CutN=:((# {. 0 , [: }: [: +/\ ])([: < [ + [: i. ])"0  ])@:[ {&.>/ [:
> >> > < ]  >
> >> >  >    (i.0) CutN i.0
> >> >  >
> >> >  >    (,0) CutN i.0
> >> >  > ┌┐
> >> >  > ││
> >> >  > └┘
> >> >  >    (,1) CutN
> >> >  10+i.1
> >> >  > ┌──┐
> >> >  > │10│
> >> >  >
> >> >  └──┘
> >> >  >    0 2 CutN 10+i.2
> >> >  > ┌┬─────┐
> >> >  > ││10 11│
> >> >  >
> >> >  └┴─────┘
> >> >  >    2 5 0
> >> >  CutN 10+i.7
> >> >  >
> >> >  ┌─────┬──────────────┬┐
> >> >  > │10 11│12 13 14 15 16││
> >> >  >
> >> >  └─────┴──────────────┴┘
> >> >  >    0 7 0 CutN 10+i.7
> >> >  >
> >> >  ┌┬────────────────────┬┐
> >> >  > ││10 11 12 13 14 15 16││
> >> >  >
> >> >  └┴────────────────────┴┘
> >> >  >
> >> >  > Cheers,
> >> >  >
> >> >  > Erling Hellenäs
> >> >  >
> >> >  >
> >> >  >
> >> >  Den 2017-10-20 kl. 10:42, skrev 'Jon Hough' via
> >> >  Programming:
> >> >  >> The problem:
> >> >  >> Let X be an array.
> >> >  >> X=: i. 50 NB.  example
> >> >  >>
> >> >  >> Let
> >> >  'split' be the percentages that each subarray takes  from X,  >> 
> >> > sequentially  >> e.g  >> split =:
> >> >  0.35 0.35 0.3 NB. first array takes 35% , second sub array
> >> >
> >> >  >> takes  35%, third takes 30%
> >> >  >> So in the end
> >> >  >>
> >> >  >> My
> >> >  solution
> >> >  >>
> >> >  >>
> >> >  splitSubs =:
> >> >  -.~&.>/\@:(i.&.>"0@:<"0)@:}.@:>.@:((+/\
> >> >  - ])@:[ (* , ])
> >> >  >> #@:])
> >> >  >>
> >> >  >> split
> >> >  splitSubs X
> >> >  >>
> >> >  >>
> >> >  >> This gives 3
> >> >  boxed arrays. Each array holds the indices to take from  X.
> >> >  >>
> >> >  >>
> >> >  There is a slight problem in that the first and second  
> >> > subarrays  >> have different  >> length, due to rounding error. I 
> >> > am  not too bothered about that  >> since,  depending on the size 
> >> > of X and the percentages, this is  >> unavoidable.
> >> >  >>
> >> >  >> Any more
> >> >  succinct, nicer solutions?
> >> >  >>
> >> >
> >> > ------------------------------------------------------------
> ----------
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> >> > 490865071867386&sdata=BzbBjTcreNzENf7febTcDhCac66Yws1z%2Fb%2Fdvg5
> >> > 9Efw%3D&reserved=0
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> >> >  >
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