See also
http://code.jsoftware.com/wiki/Essays/Progressive_Index-Of
Henry Rich
On 3/28/2018 3:14 PM, chris burke wrote:
Following up your good start:
a ,: <: +/ (* +/\"1) = a=: 1 2 1 1 2 3 2 3
1 2 1 1 2 3 2 3
0 0 1 2 1 0 2 1
a ,: <: +/ (* +/\"1) = a=: 5 6 5 5 6 5 7 6
5 6 5 5 6 5 7 6
0 0 1 2 1 3 0 2
On Wed, Mar 28, 2018 at 11:32 AM, Joe Bogner <[email protected]> wrote:
I think this is an easy one but it's escaping me. How to calculate a
running count of an item in a list?
runct (1,2,1,1,2) -: 0,0,1,2,1
runct (5,6,5,5,6) -: 0,0,1,2,1
This seems to be a good start
= (5,6,5,5,6)
1 0 1 1 0
0 1 0 0 1
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
---
This email has been checked for viruses by AVG.
http://www.avg.com
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
