After I saw your message I searched for the particular Quora problem and this is what I found,
https://www.quora.com/What-number-must-be-subtracted-from-21-38-55-and-106-each-so-that-the-remainders-technically-differences-are-proportional It seems to me that the shape of the array is restricted to be exactly 4 and the numbers do not have to be integers. Am I wrong? On Tue, Aug 14, 2018 at 7:00 PM, 'Mike Day' via Programming < programm...@jsoftware.com> wrote: > It should work on arrays of the form > a + b * i, where a and b are integer scalars, and i is an integer > vector. > So, if > q=: 6 + 7*1 2 5 11 23, > applying this function yields > (-/ .* % -/ .+)@:(2 2&$) q > 7.4 > I think you need instead something like > Difference’s greatest common divisor, > dgcd =: +./@:(2 -~/\ ]) > So > dgcd q > 7 > > It’s a bit more complicated to recover the factors, 1 2 5 ..., which seem > to be required in the Quora problem: > (](([-|~)%])dgcd) q > 1 2 5 11 23 > This works for the original array, too, > (](([-|~)%])dgcd) 21 38 55 106 > 1 2 3 6 > > And > dgcd 21 38 55 106 > 17 > > Sorry for any formatting problems - typing on iPad, > > Mike > > > Please reply to mike_liz....@tiscali.co.uk. > Sent from my iPad > > > On 14 Aug 2018, at 23:18, Jose Mario Quintana < > jose.mario.quint...@gmail.com> wrote: > > > > (-/ .* % -/ .+)@:(2 2&$)21 38 55 106 > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
