Ahh I’m sorry Linda, that was my bad copy/paste into the email …

Please ignore previous email, I have corrected the transcript below (and 
verified) so this should run without conflict (aside from being careful of 
quotes on copy/paste perhaps):

Raul’s functions:
   D=:[: (^~ >:)/ (2 3$0 1 0 1 0 0) +/ .* ]
   pmt1200=:(%<:)@D * 1 0 1 */ .# ]
   pmt=: pmt1200@(%&1200 1 1)
   pmt 5.75 240 12500
87.7604

My revised input for 13 : is also included here, as I had a mis-copy there too.
   Da=:13 : '(^~ >:)/ (2 3$0 1 0 1 0 0) +/ .* y’          NB. Removed the 
leading [: as not required for explicit (I could have left it in, but I’m 
trying to exactly reproduce Raul’s tacit definitions above), and added last 
term y to the explicit expression
   pmt1200a=: 13 : '((%<:)@Da y) * 1 0 1 */ .# y’   NB. Added last term y to 
the first and last “tine” of the fork Raul produced
   pmta=: 13 : 'pmt1200a@(%&1200 1 1) y’          NB. Added last term y 
(although this is not required as composition can be applied directly as Raul 
did without requiring explicit)

NB. Let’s compare to Raul’s solution in email below ...
   Da
[: (^~ >:)/ (2 3$0 1 0 1 0 0) +/ .* ]                           NB. Same 
definition as Raul above
   pmt1200a
(% <:)@Da * 1 0 1 */ .# ]                                       NB. Same
   pmta
pmt1200a@(%&1200 1 1)                                    NB. Same

   pmta 5.75 240 12500
87.7604                                                                 NB. 
Results match


Sorry if I confused with previous transcript paste.

…/Regards Rob


> On 13 Sep 2018, at 3:21 pm, Linda Alvord <lindaalvor...@outlook.com> wrote:
> 
> Here's a problem.  I'm not having trouble with cut and paste so could you 
> show the working version.
> 
> Also do not remove caps  [: from tacit results as they are needed for the 
> explicit versions you are writing to work correctly.
> 
> 
> D=:[: (^~ >:)/ (2 3$0 1 0 1 0 0) +/ .* ]
>   pmt1200a=:(%<:)@Da * 1 0 1 */ .#
> |value error: Da
> |   pmt1200a=:    (%<:)@Da*1 0 1*/ .#
> |[-1] c:\users\linda\j64-807-user\temp\15.ijs
> 
> 
> 
> Linda 
> 
> -----Original Message-----
> From: Programming <programming-boun...@forums.jsoftware.com> On Behalf Of 
> 'Rob Hodgkinson' via Programming
> Sent: Wednesday, September 12, 2018 11:26 PM
> To: programm...@jsoftware.com
> Subject: Re: [Jprogramming] Tacit form: How to handle intermediate
> 
> Hi Linda, Raul’s functions may be input to 13: as shown here:
> 
> Raul’s functions:
>   D=:[: (^~ >:)/ (2 3$0 1 0 1 0 0) +/ .* ]
>   pmt1200a=:(%<:)@Da * 1 0 1 */ .#
>   pmta=:pmt1200@(%&1200 1 1)
>   pmta 5.75 240 12500
> 87.7604
> 
> Revised as input to 13 :  (note in the below the space required between ’13’ 
> and ‘:’ and that I have “removed” any tacit addons (such as [:) to exactly 
> reproduce Raul’s tacit definitions ...
>   Da=:13 : '(^~ >:)/ (2 3$0 1 0 1 0 0) +/ .* y’               NB. Removed the 
> leading [: as not required for explicit (I could have left it in, but I’m 
> trying to exactly reproduce Raul’s tacit definitions above), and added last 
> term y to the explicit expression
>   pmt1200a=: 13 : '(%<:)@Da * 1 0 1 */ .# y’             NB. Added last term y
>   pmta=: 13 : 'pmt1200@(%&1200 1 1) y’                 NB. Added last term y 
> (although this is not required as composition can be applied directly as Raul 
> did) without requiring explicit)
> 
> NB. Let’s compare to Raul’s solution in email below ...
>   Da
> [: (^~ >:)/ (2 3$0 1 0 1 0 0) +/ .* ]                                NB. Same 
> definition as Raul
>   pmt1200a
> [: (% <:)@Da [: * 1 0 1 */ .# ]                                      NB. Same
>   pmta
> pmt1200@(%&1200 1 1)
>  pmta 5.75 240 12500
> 87.7604
> 
> HTH but if still unclear please expand ?
> 
> For further reference re [: only having meaning in tacit form (which is why I 
> removed it for explicit form) it may be helpful to read this link:
>       
> https://eur01.safelinks.protection.outlook.com/?url=https%3A%2F%2Fcode.jsoftware.com%2Fwiki%2FVocabulary%2Fsquarelfco&amp;data=02%7C01%7C%7Cc059f09bd44446fc424708d61928c374%7C84df9e7fe9f640afb435aaaaaaaaaaaa%7C1%7C0%7C636724060199447363&amp;sdata=OrnLHRv1N%2Fe5lnADLmIGobGEQkw5kxYmbnHMVx84AIs%3D&amp;reserved=0
>  
> <https://eur01.safelinks.protection.outlook.com/?url=https%3A%2F%2Fcode.jsoftware.com%2Fwiki%2FVocabulary%2Fsquarelfco&amp;data=02%7C01%7C%7Cc059f09bd44446fc424708d61928c374%7C84df9e7fe9f640afb435aaaaaaaaaaaa%7C1%7C0%7C636724060199447363&amp;sdata=OrnLHRv1N%2Fe5lnADLmIGobGEQkw5kxYmbnHMVx84AIs%3D&amp;reserved=0>
> 
> Thanks, Rob
> 
> 
>> On 13 Sep 2018, at 1:05 am, Linda Alvord <lindaalvor...@outlook.com> wrote:
>> 
>> 
>> 
>> When you'e're done f=: 13  :'...
>> 
>> enter
>> f
>> 
>> If the result is tacit there will be no x or y.  Instead you get a string of 
>>  separate J symbols which J uses from right to left to follow your 
>> instructions.
>> 
>> I need a laptop to check. Raul's function.
>> 
>> Linda
>> 
>> 
>> 
>> '
>> 
>> Sent from my Verizon, Samsung Galaxy smartphone
>> -------- Original message --------
>> From: Raul Miller <rauldmil...@gmail.com 
>> <mailto:rauldmil...@gmail.com>>
>> Date: 9/10/18 12:55 AM (GMT-05:00)
>> To: Programming forum <programm...@jsoftware.com 
>> <mailto:programm...@jsoftware.com>>
>> Subject: Re: [Jprogramming] Tacit form: How to handle intermediate
>> 
>> x=:0 is bad form, so I am going to ignore that part.
>> 
>> In fact, I'd eliminate all internal =: from that definition and start with:
>> 
>> pmt=: 3 : 0
>> 0 pmt y
>> :
>> 'r t b'=. y
>> D=.(1 + r % 1200) ^ t
>> b*(r % 1200) * D % D - 1
>> )
>> 
>> And our paranoia test is:
>>  pmt 5.75 240 12500
>> 87.7604
>> 
>> The next issue is that we're working with more than two values, that 
>> makes it a bit complicated.
>> 
>> On the other hand, we never use x - if it's provide we ignore it. So 
>> I'm going to ignore it here. If that bothers you, use pmt=: pmt&] f.
>> after we've got the tacit expression. (Using f. on the final 
>> expression will also protect from some damage if you happen to run the 
>> original with it's D=: expression...).
>> 
>> Anyways...
>> 
>> To simplify this slightly, notice that we never want to use the value 
>> of r. Instead, we always want r%1200. So we can divide y by 1200 1 1 
>> and work the remainder of the dyadic expression becomes:
>> 
>> pmt1200=: 3 : 0
>> 'r t b'=. y
>> D=.(1 + r) ^ t
>> b*r * D % D - 1
>> )
>> 
>> A tacit expression to compute D directly from this y would be:
>>  D=:  [: (^~ >:)/ (2 3$0 1 0 1 0 0) +/ .* ]
>> 
>> with that definition of D, pmt1200 can be
>>  pmt1200 =: (%<:)@D * 1 0 1 */ .# ]
>> 
>> and our tacit pmt becomes
>>  pmt=: pmt1200@(%&1200 1 1)
>> 
>> Trying it out:
>>  pmt 5.75 240 12500
>> 87.7604
>> 
>> Good enough?
>> 
>> --
>> Raul
>> On Sun, Sep 9, 2018 at 9:55 PM Linda Alvord <lindaalvor...@outlook.com 
>> <mailto:lindaalvor...@outlook.com>> wrote:
>>> 
>>> Here's a classic. Can anyone write this in tacit?
>>> 
>>> NB. Mortgage is Rate Months Loan
>>> 
>>> pmt=: 3 : 0
>>> (x =: 0) pmt y
>>> :
>>> 'r t b'=:y
>>> D=:(1 + r % 1200) ^ t
>>> b*(r % 1200) * D % D - 1
>>> )
>>> 
>>> pmt 5.75 240 12500
>>> 
>>> In 1961 I bought a house for $17,000. With a loan of $12,000 at 5.75 
>>> interest for 20 years. As a tenured teacher and a woman no bank would give 
>>> me a mortgage but for 20 years I payed the previous woman owner $87.77. At 
>>> the last payment it just so happened that I sold it.
>>> 
>>> Linda
>>> 
>>> -----Original Message-----
>>> From: Programming <programming-boun...@forums.jsoftware.com 
>>> <mailto:programming-boun...@forums.jsoftware.com>> On Behalf Of 'Mike 
>>> Day' via Programming
>>> Sent: Saturday, September 8, 2018 1:45 PM
>>> To: programm...@jsoftware.com <mailto:programm...@jsoftware.com>
>>> Subject: Re: [Jprogramming] Tacit form: How to handle intermediate
>>> 
>>> Agreed on the "strong hint" in herona below.  I got into that habit
>>> 
>>> years ago in Fortran....
>>> 
>>> And Sorry for the unintentional extra characters. (I'm seeing
>>> 
>>> A-circumflex where I'd typed space!) Just as well we're not talking APL!
>>> 
>>> Mike
>>> 
>>> 
>>> On 08/09/2018 09:40, Martin Kreuzer wrote:
>>>> @Linda
>>>> 
>>>> I think that your
>>>>  heron=: 13 :'%:*/(s y),(s y)-y'
>>>> looks superior to my initial approach as it gathers _all four_ 
>>>> factors under the (*/) Times Insert.
>>>> 
>>>> btw "Hope you have good classes!"
>>>> 
>>>> For quite some time, I don't have classes any more, but once in a 
>>>> while do private tutoring; my last two students finished their 
>>>> 'matura' at Easter this year (and one of them is on 'work & travel' 
>>>> in New Zealand presently).
>>>> 
>>>> @Mike
>>>> 
>>>> Looking at your 'minor change' and the resulting tacit code, 
>>>> methinks that (sy=. s - y) is giving the interpreter a much stronger 
>>>> hint that there's a re-used intemediate result than the construct (' ... [ 
>>>> s2=.
>>>> .... ') I used initially.
>>>> 
>>>> -M
>>>> 
>>>> At 2018-09-07 09:43, you wrote:
>>>> 
>>>>> Fair enough,  it looks neat,  but doesn't deal with Martin 
>>>>> Kreuzer's original requirement to apply s just the once, ie how 
>>>>> should we handle the intermediate result, s?
>>>>> 
>>>>> On the other hand, David Lambert and others propose variations on 
>>>>> how to factor the formula so as to use the result of s.
>>>>> 
>>>>> It's usually easy in explicit form,  harder in tacit form.  It 
>>>>> seems to me that using 13 : ... is very helpful in developing a 
>>>>> tacit form,  but it often fails to spot opportunities to save 
>>>>> intermediate results.  13 : ... isn't an optimising compiler - or 
>>>>> is it? It certainly doesn't spot the opportunity to save the 
>>>>> repeated (s y) in Linda's example.
>>>>> 
>>>>> Somewhat to my surprise,  a minor change to Linda's explicit 
>>>>> expression does result in a single applicaton of s in a quite 
>>>>> elegant tacit form:
>>>>> 
>>>>> Â Â Â  herona=: 13 :'%:*/sy,(sy=.s y)-y'
>>>>> 
>>>>> Â Â Â  herona 3 4 5
>>>>> 
>>>>> 
>>>>> 
>>>>> Â Â Â  herona 5 12 13
>>>>> 
>>>>> 30
>>>>> 
>>>>> Â Â Â  herona
>>>>> 
>>>>> [: %: [: */ s ([ , -) ]
>>>>> 
>>>>> 
>>>>> Cheers,
>>>>> 
>>>>> Mike
>>>>> 
>>>>> On 07/09/2018 08:19, Linda Alvord wrote:
>>>>>> It keeps getting simpler:
>>>>> 
>>>>>> s=: 13 :'-:+/y'
>>>>>> heron=: 13 :'%:*/(s y),(s y)-y'
>>>>>> heron 3 4 5
>>>>>> heron 4 5 6
>>>>>> d
>>>>> 
>>>>> 
>>>>>> ;:'[: -: +/'
>>>>> 
>>>>>> heron
>>>>> 
>>>>>> ;:'[: %: [: */ s , s - ]'
>>>>>> 
>>>>> 
>>>>>> Explisit sentences are like English and the new language is the 
>>>>>> computers J anguage.  First learn the words and then learn to read 
>>>>>> ghe ords in sentences. And just as you might when learning 
>>>>>> Spanish, you might in time begin to speak it.
>>>>> 
>>>>>> Linda
>>>>> 
>>>>> 
>>>>>> -----Original Message-----
>>>>>> From: Programming <programming-boun...@forums.jsoftware.com> On 
>>>>>> Behalf Of David Lambert
>>>>>> Sent: Thursday, September 6, 2018 6:11 PM
>>>>>> To: programming <programm...@jsoftware.com>
>>>>>> Subject: Re: [Jprogramming] Tacit form: How to handle intermediate
>>>>> 
>>>>>> A hook can save recomputation.
>>>>> 
>>>>>> (computation with original data and reused me)Â  (resuse me)
>>>>> 
>>>>> 
>>>>>> Â Â  test=: [: %: ([: -: +/) * [: */ ([: -: +/) - ]
>>>>> 
>>>>>> Â Â  NB. play with the half factor  Â Â  f=:Â Â Â  4 %~ [: %: [: 
>>>>>> */ (([ , (- +:))~ +/)
>>>>> 
>>>>>> Â Â  NB. shorter
>>>>> 
>>>>>>    NB.    c o m p u t a t i o n    r e u s e     g=:  
>>>>>> Â  ([: %: [: */ [ , -)~Â Â Â Â  ([: -: +/)
>>>>> 
>>>>>> Â Â  g2=:Â Â  ([: %: [: */ [ , -)~ -:@:(+/)
>>>>> 
>>>>> 
>>>>>> Â Â  %/ (g , test) 3?@:$0
>>>>>> 1
>>>>> 
>>>>> 
>>>>>> On 09/04/2018 08:00 AM, programming-requ...@forums.jsoftware.com wrote:
>>>>>>> Date: Tue, 04 Sep 2018 11:50:43 +0000
>>>>>>> From: Martin Kreuzer<i...@airkreuzer.com> 
>>>>>>> To:programm...@jsoftware.com
>>>>>>> Subject: [Jprogramming] Tacit form: How to handle intermediate
>>>>>>>       result..?
>>>>>>> Message-ID:
>>>>>>> <5b8e71a5.1c69fb81.65e5c.4a9esmtpin_added_miss...@mx.google.com>
>>>>>>> Content-Type: text/plain; charset="us-ascii"; format=flowed
>>>>>>> 
>>>>>>> Hi all -
>>>>>>> 
>>>>>>> To calculate the area of a flat triangle, using Heron's formula, 
>>>>>>> A(a,b,c)= sqrt( s2*(s2-a)*(s2-b)*(s2-c) ) I wrote a simple 
>>>>>>> function doing this:
>>>>>>> 
>>>>>>> * get the three sides (as list input y)
>>>>>>> * compute the half  perimeter s2
>>>>>>> * build the differences s2-y
>>>>>>> * build product
>>>>>>> * take square root
>>>>>>> 
>>>>>>> My explicit solution looks like this
>>>>>>> 
>>>>>>> taher=: 13 : '%: s2 * */ s2-y [ s2=. -: +/ y'
>>>>>>> 
>>>>>>> and works
>>>>>>> 
>>>>>>>     taher 3 4 5
>>>>>>> 6
>>>>>>> 
>>>>>>> Suggested tacit version looks like this (and works too)
>>>>>>> 
>>>>>>> tahert=: [: %: ([: -: +/) * [: */ ([: -: +/) - ]
>>>>>>> 
>>>>>>> Q: Is there a way to reference the intermediate result of ([: -:
>>>>>>> +/) the half perimeter s2 within the tacit expression, as has 
>>>>>>> +been
>>>>>>> done in the explicit..?
>>>>>>> [Guess the interpreter takes care of this anyway; my question 
>>>>>>> aims at whether a shorter formulation could be reached.]
>>>>>>> 
>>>>>>> Thanks
>>>>>>> -M
>>>>>> ------------------------------------------------------------------
>>>>>> --
>>>>>> --
>>>>>> For information about J forums see 
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>>>>>> 68 
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