It's not a matter of monadic/dyadic. This conjunction does not refer to
x or y, and so the body is executed when it receives the u and v
operands. I don't think the language specifies which 'valence' will be
executed if both are defined; apparently it is the dyad.
Henry Rich
On 10/7/2018 7:36 PM, Linda Alvord wrote:
Pascal, did you mean something like this? Your a2 has an error.
a=: 2 : ('u@v';':';'u v')
a3=: 0 :('u@V';':';'U V')
a
2 : 0
u@v
:
u v
)
a3
┌───┬─┬───┐
│u@V│:│U V│
└───┴─┴───┘
I don’t know what this thread id abouttt. This is just a guess.
Linda
-----Original Message-----
From: Programming <[email protected]> On Behalf Of
'Pascal Jasmin' via Programming
Sent: Saturday, October 6, 2018 8:39 PM
To: Programming Forum <[email protected]>
Subject: [Jprogramming] bug in j806 (I think) ambivalent explicit conjunction
a =: 2 : ('u@v';':';'u v')
a2 : 0u@v:u v)
so far so good...
- a +- +
it just assumes that result expression is dyadic workaround is to use tacit
version of : in return value of a, but this doesn't seem like it is working
right.
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