/ IS rank alone.
x u/ y is defined as
x u"(lu,_) y
where lu is the left rank of u. Apply each CELL of x to the ENTIRE y.
Henry Rich
On 11/12/2018 7:00 PM, Joe Bogner wrote:
Thanks all. The solutions above were more complicated than I expected. I
had assumed I was missing something obvious. The obvious miss was to use /
... I was thinking I could do something with rank alone
For comparison it is combination of map and reduce in javascript
['Joe B','Joe Q','Bobby Z','Janet F'].map(function(x) { return
['Joe','Bob','Jane'].reduce(function(acc,y,idx) { return
x.indexOf(y)>=0?idx:acc },-1) })
[0, 0, 1, 2]
On Mon, Nov 12, 2018 at 6:17 PM 'Mike Day' via Programming <
[email protected]> wrote:
or this variant?
f(1 i.~"1+./@E.~&> /)s. NB. f & s obvious?
0 0 1 2
This lists the index of the first instance of a substring of each element
of fullNames in the
shortNames boxed list. It assumes it's there somewhere, but you can use
the property
that non-inclusion is shown by index = length or number of shortNames.
Any help,
Mike
On 12 Nov 2018, at 22:29, Brian Schott <[email protected]> wrote:
Is this anything you can use?
I.fullNames(((]))&: >"0/-:"1 ((#@]{.[))& >"0/) shortNames
--
(B=) <-----my sig
Brian Schott
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