I do not recall saying that tacitness was a requirement.

Sent from my iPhone

> On Nov 28, 2018, at 6:23 PM, Raul Miller <[email protected]> wrote:
> 
> Hmm..
> 
> When I look at explanations of the Y combinator, I don't see any
> requirement that the implementations must be tacit.  For example:
> https://en.wikipedia.org/wiki/Fixed-point_combinator#Fixed_point_combinators_in_lambda_calculus
> 
> Instead, I see an entirely symbolic representations (where, granted,
> the symbols are eventually intended to refer to implementations).
> 
> Put different: the use of references to memory which is not intended
> to be changed is not usually thought of as "state" even though that
> memory could be changed.
> 
> That said, I will agree that it's possible to think of all memory as
> "state". I think this would mean that only logic implemented purely in
> hardware is "not state".
> 
> That said, I will also agree that within a J environment, you aren't
> going to be able to changed unnamed function implementations while
> they're running without cheating (or, perhaps, being cheated). So, ...
> there's that.
> 
> Thanks,
> 
> -- 
> Raul
> 
> On Wed, Nov 28, 2018 at 5:38 PM Jose Mario Quintana
> <[email protected]> wrote:
>> 
>>> [Aside: if I remember right, you wrote the tacit version there at rosetta
>> code?]
>> 
>> That is right.
>> 
>>> After sleeping on this thread for a few days, I've finally realized
>>> that I don't have any idea what you mean by "ad hoc encodings".
>>> 
>>> If you have time for some questions: What does "ad hoc encodings"
>>> mean? Is that a good thing or a bad thing? Why?
>> 
>> As far as I can see, when the argument of Y, the higher-order function, for
>> which the product of Y is a fixed-point, is represented by means of
>> standard code associated with recursions in J then one can produce
>> relatively simple versions of Y which are, as much as possible (given the
>> lack of direct support of higher-order functions as arguments by the
>> current official interpreters), in compliance with the specifications of
>> the Rosetta Code (RC) task.
>> 
>> (Beware of line-wrapping)
>> 
>> As an illustration, this is a comparison between the slightly revised
>> version of my non-tacit version of the Y combinator for monadic recursions,
>> 
>>   X=. 1 :'<(<,'':''),<(<1;~":0),<(":0);,(''u u`:6('',(5!:5<''u''),'')`:6
>> y'')'(1 :'u u`:6')
>> 
>> renamed as X to be able to distinguish it from the explicit version of Y in
>> the RC entry,
>> 
>>   Explicit alternate implementation
>> 
>> https://rosettacode.org/wiki/Y_combinator#Explicit_alternate_implementation
>> 
>> (which I suppose you wrote).
>> 
>> Using recursive computations of factorials as an example,
>> 
>>   M=. 1 :'1:`(* u@:<:)@.*'
>>   M=. (5!:1)<'M'
>> 
>> Due to J`s aforementioned limitation, it is unavoidable the use of a
>> representation of the adverb (i.e., the higher-order function), the AR of
>> the adverb (M) is chosen as the argument for X,
>> 
>>   M X                ("0) i.11
>> 1 1 2 6 24 120 720 5040 40320 362880 3628800
>> 
>> This argument is closely related to usual ways to define recursive verbs,
>> 
>>   (    $:M`:6)       ("0) i.11
>> 1 1 2 6 24 120 720 5040 40320 362880 3628800
>>   (f=. f M`:6)       ("0) i.11
>> 1 1 2 6 24 120 720 5040 40320 362880 3628800
>> 
>> or, more generaly,
>> 
>>   (f=. 3 :'f M`:6 y')("0) i.11
>> 1 1 2 6 24 120 720 5040 40320 362880 3628800
>> 
>>   M=. 1 :'if. * y do. y * u <: y else. 1 end.'
>>   M=. (5!:1)<'M'
>> 
>>   (f=. 3 :'f M`:6 y')("0) i.11
>> 1 1 2 6 24 120 720 5040 40320 362880 3628800
>> 
>> In contrast, Y (as per the explicit RC J entry) is a noun (and a gerund)
>> and by itself does not produce anything,
>> 
>>   wrap=. _66 [\ (5!:5)@:<
>> 
>>   wrap'Y'
>> ,<(<,':'),<(<(,'0');3),<(,'0');3 21$'g=.y                   recur=
>> . sivelY`:6 g  recur`:6 recur     '
>> 
>> Not surprisingly, the argument for Y Ev (Ev is a name referring to `:6) is
>> also a noun (and a gerund) and by itself does not produce anything either,
>> 
>>   wrap'almost_factorial'
>> ,<(<(<,':'),<(<(,'0');2),<(,'0');5 26$'  if. (_1 {:: m) <: #m do.
>>   v |. y;_1 }. m          else.                       (y;m) Defer
>> v`''''        end.                    '),<(<(<,'0'),<,<2),<(<,':'
>> ),<(<(,'0');3),<(,'0');3 25$'''f n''=.y                   if. 0 >:
>> n do. 1         else. n * f`:6 n-1 end.'
>> 
>> and, it seems, its particular purpose is to be used as an argument for (Y
>> Ev).
>> 
>> On the one hand, regarding the recursive verbs produced by each of the
>> combinators,
>> 
>>   v=. (Y Ev almost_factorial)Ev
>> 
>> is a verb,
>> 
>>   wrap'v'
>> ((<,<(<(<,':'),<(<(,'0');2),<(,'0');5 26$'  if. (_1 {:: m) <: #m d
>> o.    v |. y;_1 }. m          else.                       (y;m) De
>> fer v`''''        end.                    '),<(<(<,'0'),<(<,<(<(<,
>> ':'),<(<(,'0');2),<(,'0');5 26$'  if. (_1 {:: m) <: #m do.    v |.
>> y;_1 }. m          else.                       (y;m) Defer v`''''
>>        end.                    '),<(<(<,'0'),<,<2),<(<,':'),<(<(,
>> '0');3),<(,'0');3 25$'''f n''=.y                   if. 0 >: n do.
>> 1         else. n * f`:6 n-1 end.'),<2),<(<,':'),<(<(,'0');3),<(,'
>> 0');2 29$'''g recur''=.y                   (recursivelY`:6 g)`:6 r
>> ecur'),(<,<(<(<,':'),<(<(,'0');2),<(,'0');5 26$'  if. (_1 {:: m) <
>> : #m do.    v |. y;_1 }. m          else.                       (y
>> ;m) Defer v`''''        end.                    '),<(<(<,'0'),<,<2
>> ),<(<,':'),<(<(,'0');3),<(,'0');3 25$'''f n''=.y
>> if. 0 >: n do. 1         else. n * f`:6 n-1 end.'),<3) (2 : 0) (3
>> : 0)
>> 'g recur x'=.y
>>  (g`:6 recur`:6 recur)`:6 x
>> )
>> 
>>  if. (_1 {:: m) <: #m do.
>>    v |. y;_1 }. m
>>  else.
>> 
>>    (y;m) Defer v`''
>>  end.
>> 
>> )
>> 
>> and this linear representation of (Y Ev almost_factorial)Ev is incomplete;
>> in other words, the verb produced is not stateless and consequently it is
>> vulnerable to reassignments,
>> 
>>   (Y Ev almost_fibonacci)Ev ("0) i. 11
>> 0 1 1 2 3 5 8 13 21 34 55
>> 
>>   Defer=. 1
>> 
>>   (Y Ev almost_fibonacci)Ev ("0) i. 11
>> |syntax error
>> |       (y;m)Defer v`''
>> 
>> Thus, the explicit entry in RC is not an implementation of the Y combinator
>> complying with the specifications.
>> 
>> On the other hand, the verb produced by M X is stateless and relatively
>> very simple,
>> 
>>   u=. M X
>>   wrap'u'
>> <(<,':'),<(<(,'0');1),<<;._1 '|0|u u`:6(<(<,'':''),<(<(,''0'');1),
>> <(,''0'');,:''if. * y do. y * u <: y else. 1 end.'')`:6 y' (1 : 'u
>> u`:6(<(<,'':''),<(<(,''0'');1),<(,''0'');,:''if. * y do. y * u <:
>> y else. 1 end.'')`:6 y')
>> 
>> Furthermore, according to the interpreter (Y Ev almost_factorial)Ev seems
>> to be doing a lot of unnecessary stuff vs M X for the task at hand,
>> 
>>   stp=. ] (([ ((<;._1 '|Sentence|Space|Time|Space * Time') , (, */&.:>@:(1
>> 2&{))@:(] ; 7!:2@:] ; 6!:2)&>) (10{a.) -.&a:@:(<;._2@,~) ]) [ (0 0 $
>> 13!:8^:((0 e. ])`(12"_)))@:(2 -:/\ ])@:(".&.>)@:((10{a.) -.&a:@:(<;._2@,~)
>> ]) ::(0 0&$@(1!:2&2)@:('Mismatch!'"_))) ".@:('0( : 0)'"_)
>> 
>>   stp 11
>> (Y Ev almost_factorial)Ev("0) i.11
>> M X                      ("0) i.11
>> )
>> ┌──────────────────────────────────┬───────┬──────────┬────────────┐
>> │Sentence                          │Space  │Time      │Space * Time│
>> ├──────────────────────────────────┼───────┼──────────┼────────────┤
>> │(Y Ev almost_factorial)Ev("0) i.11│1242368│0.0142416 │17693.3     │
>> ├──────────────────────────────────┼───────┼──────────┼────────────┤
>> │M X                      ("0) i.11│250304 │0.00179289│448.768     │
>> └──────────────────────────────────┴───────┴──────────┴────────────┘
>> 
>> I hope it helps
>> 
>> 
>> On Mon, Nov 19, 2018 at 7:11 PM Jose Mario Quintana <
>> [email protected]> wrote:
>> 
>>> I am on vacation this week.  I will have more time (and access to a PC)
>>> when I get back.
>>> 
>>>> On Monday, November 19, 2018, Raul Miller <[email protected]> wrote:
>>>> 
>>>> [Aside: if I remember right, you wrote the tacit version there at rosetta
>>>> code?]
>>>> 
>>>> After sleeping on this thread for a few days, I've finally realized
>>>> that I don't have any idea what you mean by "ad hoc encodings".
>>>> 
>>>> If you have time for some questions: What does "ad hoc encodings"
>>>> mean? Is that a good thing or a bad thing? Why?
>>>> 
>>>> Thanks,
>>>> 
>>>> --
>>>> Raul
>>>> 
>>>> 
>>>> 
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