Sorry, Bob, I hadn’t seen this when I sent something similar a moment ago,

Mike

Please reply to [email protected].      
Sent from my iPad

> On 4 Dec 2018, at 15:53, 'robert therriault' via Programming 
> <[email protected]> wrote:
> 
> Hi Linda,
> 
> The first time you applied them to identical strings, but as you continue 
> applying |. with each iteration the strings begin to differ from one another.
> 
>     ([: +/\ |.)1 1  NB. First iteration
> 1 2
>   |. ([: +/\ |.)1 1  NB. Beginning of second, we reverse the string
> 2 1
>   +/\ |. ([: +/\ |.)1 1  NB. Build the sum, complete the second iteration
> 2 3
>   ([: +/\ |.) ([: +/\ |.)1 1  NB. Equivalent to the above line
> 2 3
>   |. ([: +/\ |.) ([: +/\ |.)1 1  NB. Beginning of third, we reverse the 
> preceding result
> 3 2
>   +/\ |. ([: +/\ |.) ([: +/\ |.)1 1 NB. Build the sum, completing the third 
> iteration
> 3 5
>   ([: +/\ |.) ([: +/\ |.) ([: +/\ |.)1 1  NB. Equivalent to the above line 
> 3 5
> 
> Now with | instead of |.
> 
>    ([: +/\ |)1 1  NB. First iteration
> 1 2
>   | ([: +/\ |)1 1  NB. Beginning of second, string is not reversed
> 1 2
>  +/\ | ([: +/\ |)1 1   NB. Build the sum, complete the second iteration
> 1 3
>   ([: +/\ |) ([: +/\ |)1 1  NB. Equivalent to the above line
> 1 3
>  | ([: +/\ |) ([: +/\ |)1 1  NB. Beginning of third, string is not reversed
> 1 3
>  +/\  | ([: +/\ |) ([: +/\ |)1 1  NB. Build the sum, completing the third 
> iteration
> 1 4
>   ([: +/\  |) ([: +/\ |) ([: +/\ |)1 1   NB. Equivalent to the above line
> 1 4
> 
> Hope this helps.
> 
> Cheers, bob 
> 
>> On Dec 4, 2018, at 1:59 AM, Linda Alvord <[email protected]> wrote:
>> 
>> Mike, All I did was apply  [:+/\  to two things that were identical. And got 
>> different answers.
>> 
>> ($|i.6);$|.i.6
>> ┌─┬─┐
>> │6│6│
>> └─┴─┘
>>  (|^:(i.6)1 1);|.^:(i.6)1 1  
>> ┌───┬───┐
>> │1 1│1 1│
>> │1 1│1 1│
>> │1 1│1 1│
>> │1 1│1 1│
>> │1 1│1 1│
>> │1 1│1 1│
>> └───┴───┘
>>  (([:+/\|)^:(i.6)1 1);([:+/\|.)^:(i.6)1 1
>> ┌───┬────┐
>> │1 1│1  1│
>> │1 2│1  2│
>> │1 3│2  3│
>> │1 4│3  5│
>> │1 5│5  8│
>> │1 6│8 13│
>> └───┴────┘
>> Linda
>> 
>> -----Original Message-----
>> From: Programming <[email protected]> On Behalf Of 
>> 'Mike Day' via Programming
>> Sent: Tuesday, December 4, 2018 4:04 AM
>> To: [email protected]
>> Subject: Re: [Jprogramming] Revisisting the Y combinator
>> 
>> Does this help?
>> 
>>   <\i.4
>> +-+---+-----+-------+
>> |0|0 1|0 1 2|0 1 2 3|
>> +-+---+-----+-------+
>>   <\.i.4
>> +-------+-----+---+-+
>> |0 1 2 3|1 2 3|2 3|3|
>> +-------+-----+---+-+
>>   <\.|.i.4
>> +-------+-----+---+-+
>> |3 2 1 0|2 1 0|1 0|0|
>> +-------+-----+---+-+
>> 
>> Mike
>> 
>> 
>> 
>>> On 04/12/2018 07:50, Linda Alvord wrote:
>>> Here's the step that I can't understand in the Fibonacci series. How is  l 
>>> different from  |.  ?
>>> 
>>> ($|i.6)-:$|.i.6
>>> 1
>>>   (|^:(i.6)1 1)-:|.^:(i.6)1 1
>>> 1
>>>   (([:+/\|)^:(i.6)1 1)-:([:+/\|.)^:(i.6)1 1
>>> 0
>>> 
>>> 
>>>   (([:+/\|)^:(i.6)1 1);([:+/\|.)^:(i.6)1 1 ┌───┬────┐
>>> │1 1│1  1│
>>> │1 2│1  2│
>>> │1 3│2  3│
>>> │1 4│3  5│
>>> │1 5│5  8│
>>> │1 6│8 13│
>>> └───┴────┘
>>> Linda
>>> 
>>> -----Original Message-----
>>> From: Programming <[email protected]> On Behalf 
>>> Of lindaalvord
>>> Sent: Monday, December 3, 2018 11:27 PM
>>> To: [email protected]
>>> Subject: Re: [Jprogramming] Revisisting the Y combinator
>>> 
>>> Sorry, Jose, I didn't look. 55 is the 10th term!
>>> Linda
>>> 
>>> 
>>> Sent from my Verizon, Samsung Galaxy smartphone
>>> -------- Original message --------From: Jose Mario Quintana 
>>> <[email protected]> Date: 12/3/18  8:20 PM  (GMT-05:00) 
>>> To: [email protected] Subject: Re: [Jprogramming] Revisisting 
>>> the Y combinator Linda,
>>> 
>>> Please check the Rosetta Code page, I did not produce the Fibonacci 
>>> sequence, I just showed
>>> 
>>>   FIB Y 10
>>> 55
>>> 
>>> and almost everybody there agrees (and apparently so did Binet and de 
>>> Moivre).
>>> 
>>> Raul showed the sequence 0 1 1 2 ... and he was not the only one.
>>> Personally, I have no problem at all with that given the context.
>>> 
>>> I hope it helps
>>> 
>>> 
>>> 
>>> On Mon, Dec 3, 2018 at 7:30 PM Linda Alvord 
>>> <[email protected]>
>>> wrote:
>>> 
>>>> Jose, If you look up the derivation of the fibonnaci series was 
>>>> developed you will find  1 1 2 3 5 . . .
>>>> 
>>>> I think it should be left out of an example of the Y form. Or, maybe 
>>>> it can be modified to come out correctly.
>>>> 
>>>> I do have a way to generate the correcg formula and feel 
>>>> mathematicians will be more comfortable with that.
>>>> 
>>>> 
>>>> Linda
>>>> 
>>>> 
>>>> 
>>>> -----Original Message-----
>>>> From: Programming <[email protected]> On 
>>>> Behalf Of Jose Mario Quintana
>>>> Sent: Monday, December 3, 2018 6:18 PM
>>>> To: [email protected]
>>>> Subject: Re: [Jprogramming] Revisisting the Y combinator
>>>> 
>>>> Linda,
>>>> 
>>>> The choice to start the Fibonacci sequence at 0 is to conform with 
>>>> some of the other answers at the Rosetta Code page,
>>>> 
>>>>    Y combinator
>>>> 
>>>> https://eur03.safelinks.protection.outlook.com/?url=https%3A%2F%2Fros
>>>> e 
>>>> ttacode.org%2Fwiki%2FY_combinator&amp;data=02%7C01%7C%7C4673109620904
>>>> e
>>>> 6c73d008d659a0b678%7C84df9e7fe9f640afb435aaaaaaaaaaaa%7C1%7C0%7C63679
>>>> 4
>>>> 944120539237&amp;sdata=VUhCaXruQBmADyjRuo3MnUsfN9Nt7wtPqv%2F6ky5r9Mw%
>>>> 3
>>>> D&amp;reserved=0
>>>> 
>>>> Most people start numbering items at 1 and when producing a function
>>>> (Fib) for the Fibonacci sequence the correspondence is,
>>>> 
>>>>    1 2 3 4 5 6  7  8  9 10 ...
>>>>    1 1 2 3 5 8 13 21 34 55 ...
>>>> 
>>>> Some of us, and J, start numbering items at 0.  So we can use the 
>>>> correspondence,
>>>> 
>>>>  0 1 2 3 4 5 6  7  8  9 10 ...
>>>>  0 1 1 2 3 5 8 13 21 34 55 ...
>>>> 
>>>> So, either way, Fib(10) is 55 and we all agree even if we disagree.
>>>> 
>>>> (Apparently, the Fibonacci function can be extended to the complex 
>>>> plane and beyond using, the so-called, Binet's formula.)
>>>> 
>>>> I hope it helps
>>>> 
>>>> 
>>>> On Thu, Nov 29, 2018 at 10:40 PM Linda Alvord 
>>>> <[email protected]>
>>>> wrote:
>>>> 
>>>>> Jose,  Somehow this surprised me.
>>>>> 
>>>>> Y=: ($:`)(`:6)
>>>>>    N=: 1 :'(u@:<:@:<: + u@:<:)^:(1 < ])'
>>>>>     P=: (5!:1)<'N'
>>>>>     P Y("0) i.11
>>>>> 0 1 1 2 3 5 8 13 21 34 55
>>>>> 
>>>>>    Y
>>>>> ($:`)(`:6)
>>>>>    N
>>>>> 1 : '(u@:<:@:<: + u@:<:)^:(1 < ])'
>>>>>    P
>>>>> ┌────────────────────────────────────────────┐
>>>>> │┌─┬────────────────────────────────────────┐│
>>>>> ││:│┌─────┬────────────────────────────────┐││
>>>>> ││ ││┌─┬─┐│┌─┬────────────────────────────┐│││
>>>>> ││ │││0│1│││0│(u@:<:@:<: + u@:<:)^:(1 < ])││││ ││ 
>>>>> ││└─┴─┘│└─┴────────────────────────────┘│││
>>>>> ││ │└─────┴────────────────────────────────┘││
>>>>> │└─┴────────────────────────────────────────┘│
>>>>> └────────────────────────────────────────────┘
>>>>> 
>>>>> 
>>>>> Linda
>>>>> 
>>>>> 
>>>>> 
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