Thanks Bob - nice!
I think you could avoid the boxing using:
pad=: _3&({.!.'0')@":"0
On Tue, Feb 19, 2019 at 4:39 PM 'robert therriault' via Programming <
[email protected]> wrote:
> Hey Ric,
>
> I get a chance to repay the favour of helping me out on StackOverflow
> yesterday.
> This solution relies on some boxing, but it does use fill at its core.
>
> And yes Skip it does end up with a literal result.
> I don't know of a way around that, but I would be happy to be proved wrong
> as well!
>
> a
> 0 12 34 678 20
> pad=: > @ (_3&({.!.'0') @ ": each)
> pad a
> 000
> 012
> 034
> 678
> 020
>
> Cheers, bob
>
> > On Feb 18, 2019, at 6:00 PM, Ric Sherlock <[email protected]> wrote:
> >
> > ('r<0>0.0' 8!:2 ]) ,. a
>
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