Hi, From the dictionary page on # :
The complex left argument a j. b copies a items followed by b fills. Also from the dictionary, we get that #’s rank is _ 1 _, so we can suppose the left argument is a vector. In that case each atom of the left argument must match an item of the right (scalars left arguments are extended). So what you’d want for your later examples is 1j6 1 1 # 10 11 12 which gives 1 copy of 10, followed by 6 fill items (0), and then preserves 11 and 12. Couldn’t really understand what you were trying to do with b and a. Hope this helps! Cheers, Louis > On 27 Apr 2019, at 17:01, Brian Schott <[email protected]> wrote: > > I have a list `b =. ,a` where a is defined below. b always contains 6 > (real) atoms, not necessarily the values in the current example a. > > I want to produce b using complex x values in Copy but cannot seem to get > the correct x to do so. > > ]a =: 10+i. 2 3 > 10 11 12 > 13 14 15 > (0,.~0,.0,~0,])a > 0 0 0 0 0 > 0 10 11 12 0 > 0 13 14 15 0 > 0 0 0 0 0 > [b =. ,(0,.~0,.0,~0,])a > 0 0 0 0 0 0 10 11 12 0 0 13 14 15 0 0 0 0 0 0 > > Below are my attempts at learning to use complex x in Copy. > > 0j6 # 4 > 0 0 0 0 0 0 > 0j6 1 # 4 > 0 0 0 0 0 0 4 > > The above examples seemed to provide me a guideline, but when I try similar > examples with a list right hand argument, I seem to lose the (leading) 10 > when I don't get a length error. > > 0j6 1 1 1# 10 11 12 > |length error > | 0j6 1 1 1 #10 11 12 > 0j6 1 1 # 10 11 12 > 0 0 0 0 0 0 11 12 > 0j6 1 1 1 # 10 11 12 > |length error > | 0j6 1 1 1 #10 11 12 > > How do I get the desired result b(and preserve the 10 in the simpler > examples)? > > -- > (B=) <-----my sig > Brian Schott > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
