A slightly more gentle approach to the problem solved as Pascal gave is to
use the magical `13 :` construct as shown below; force the first 2 steps
into just one line and call the argument y .

   a=.(>&6) (2+i.9)
   a# (2+i.9)
7 8 9 10
   13 : 'a#y[a=.(>&6) y'  NB. 13 : produces a tacit result when it can
>&6 # ]
   (>&6 # ]) 2+i.9
7 8 9 10

-- 
(B=)
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