Perhaps
array e. 6 15 10
is what you are really trying to do?
Henry Rich
On 6/12/2019 10:49 AM, 'Rob Hodgkinson' via Programming wrote:
JmageK, also try to experiment with the adverb / (“table”) when you supply the
verb “=“ as its argument.
12$i.5
0 1 2 3 4 0 1 2 3 4 0 1
2 3 1 =/ 12$i.5
0 0 1 0 0 0 0 1 0 0 0 0
0 0 0 1 0 0 0 0 1 0 0 0
0 1 0 0 0 0 1 0 0 0 0 1
+/“1 ] 2 3 1 =/ 12$i.5
2 2 3
+/"1]6 15 10 =/ i.201
1 1 1
…/Rob
On 13 Jun 2019, at 12:40 am, 'Pascal Jasmin' via Programming
<[email protected]> wrote:
6 15 10 +/@:="0 1 i.201
1 1 1
6 15 10 +/@:="0 _ i.201 1 1
On Wednesday, June 12, 2019, 9:27:08 a.m. EDT, JmageK <[email protected]>
wrote:
(([: +/ =&6) , ([: +/ =&10) , ([: +/ =&15)) i.201 1 1
How can I generate the above code for abirary comparison to i.20(example input)
without repeating myself? I get errors if I try any variations of the following
f=: 3 : '([: +/ x=y)'
2 f i.5| domain error
Thanks in advance.
JmageK
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