Hmm...
({.% */@}.) 1 2 3 4 5
would actually work if we replaced 1 2 3 4 5 with an arbitrary
different list of numbers.
It would not work, though, if we replaced % with a different verb.
Thanks,
--
Raul
On Thu, Oct 3, 2019 at 5:22 PM Nollaig MacKenzie
<noll...@amhuinnsuidhe.net> wrote:
>
> I'm guessing
>
> %*/2 3 4 5
>
> wouldn't count....
>
>
> On 2019.10.02 23:43:40, you,
> the extraordinary Skip Cave, spake thus:
> >
> > I can write:
> > 1%(2%(3%(4%5)))
> >
> > 1.875
> >
> >
> > Using insert, I can simplify:
> >
> > %/1 2 3 4 5
> >
> > 1.875
> >
> >
> > Now I can write:
> >
> > (((1%2)%3)%4)%5
> >
> > 0.00833333333333333
> >
> >
> > How can I use insert to simplify this?
> >
> >
> > Skip Cave
> > ----------------------------------------------------------------------
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>
> --
> Nollaig MacKenzie
> ftp://ftp.nollaig.ca/pub/pap/
> pgp key C6E9845A
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