The current implementation is as you left it for this case.

>./vec times.

Henry Rich

On 3/5/2020 1:09 PM, Roger Hui wrote:
u is a verb and vec is a vector of non-negative integers.  In u:vec 0, in
the current implementation, is u invoked +/vec times or >./vec times?

(Sorry if you are seeing this twice.  Apparently my first post disappeared.)
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