I don't know what the debug commands are supposed to do. If anyone
knows and can put it into NuVoc that would be great.
I rewrote the whole interface to debug in 9.01 so there is a good chance
some things don't work right. Several such places have been fixed, but
if you know you have an error and can give a reproducible testcase, send
it to me.
Henry Rich
On 4/1/2020 2:45 PM, Brian Schott wrote:
All,
I think Bill's solution works for my question: dbover'' (13!:20).
In contrast to Gilles, I think dbinto'' (13!:21) works as designed, because
changing the value of t to 99 does not change the code in line [0], which
it then executes with dbinto or dbover.
It is rather difficult to find the names and descriptions of each of the
dbxxx verbs. The information is scattered and incomplete. I found a rather
good brief page (in a link hidden on the NuVoc page under the name
Foreigns). But it does not have dbinto and dbout which are pronouns for
13!:n's, and I don't know where one finds dbstop and dbstops defined.
https://code.jsoftware.com/wiki/Vocabulary/Foreigns
https://www.jsoftware.com/help/dictionary/dx013.htm is also helpful, but
outdated and does not tell the shortcut dbnames at all.
Returning to my original question, but changing it a little to ask how to
NOT run the current line but force the debugger to stop before the next
line even though it has not been stopped, requires assumptions and two
steps.
The assumption is that a set stop has lead to the current line.
Step 1 is setting a stop on the next line. An easy way to do this is use
dbstops'<this verbs name>' to set stops everywhere in this verb.
Step 2 is to dbnxt'' .
So for example, consider these steps:
h=: 3 : ('t=. 2 3*y'; '1+t'; 't')
dbss'h 0'
dbr 1
3 4,h 5 6 7
|stop: h
| t=.2 3*y
|h[0]
dbsq'' NB. queries what stops are active
h 0
dbstops'h' NB. or dbstop'h'
dbsq''
h *:*;
dbnxt'' NB. continue on the next line without doing this line
|stop
| 1+t
|h[1]
NB. remember here, t has never been assigned a value, so 1+t is an
error
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