sum (insert) and count apply to items. The items are the rows. +/ 3 2 $ 1 2 3
6 6 the result is a list. If there is just 1 column (one result), it is still a list. On Wednesday, April 15, 2020, 01:33:35 p.m. EDT, Thomas Bulka <[email protected]> wrote: Hello everyone, I do have some difficulties in understanding a certain behavior. Let's assume, I define the classical mean verb, a row vector and a column vector: mean =: +/ % # rvec =: 1 2 3 cvec =: 3 1 $ 1 2 3 When I apply mean to rvec I get the result 2 (as expected), which happens to be a scalar ($$ mean rvec yields 0). When I apply mean to cvec the result is a vector ($$ mean cvec yields 1). I'd like to understand, why this behavior has been chosen. Do you have any hints for me? Regards, Thomas ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
