Yes, I know... I should have offered 4 p: 1 2 3 4x or something similar.

Cheers,

Mike

Sent from my iPad

> On 25 Apr 2020, at 13:20, Henry Rich <[email protected]> wrote:
> 
> The bug seems to be confined to the argument 1x .  4 p: x searches x+2, x+4, 
> ... for primes.  It starts at x+1 if x is even or is non-extended 1; but for 
> extended 1 it starts at x+2.
> 
> Henry Rich
> 
>> On 4/25/2020 4:48 AM, 'Michael Day' via Programming wrote:
>> Investigating how to factor quite large numbers in J,  I've just bumped into 
>> this curiosity, which
>> 
>> wrecked my loopy experiment at an early stage!...
>> 
>>    4 p: 1
>> 2
>>    4 p: 1x   NB. need to try extended in some cases...
>> 3
>> 
>> !
>> 
>> Thanks for any advice,
>> 
>> Mike
>> 
>> 
>>> On 25/04/2020 00:15, 'Mike Day' via Programming wrote:
>>> Numbers of divisors below, not the divisors themselves... the thread had 
>>> split! I was attempting to comment on Hauke Rehr’s post.
>>> M
>>> 
>>> Sent from my iPad
>>> 
>>>> On 24 Apr 2020, at 23:52, 'Jon' via Programming 
>>>> <[email protected]> wrote:
>>>> 
>>>> This is missing a few divisors. It seems Skip's original method would be 
>>>> difficult to beat. It's O(n) in time and space. You could improve space 
>>>> complexity by doing a simple loop, but as far as I can see there are no 
>>>> shortcuts, and the best way is to just "brute force" it.
>>>> 
>>>> ⁣Sent from BlueMail ​
>>>> 
>>>>> On Apr 25, 2020, 5:35 AM, at 5:35 AM, 'Mike Day' via Programming 
>>>>> <[email protected]> wrote:
>>>>> I think this is near to the approved way:
>>>>> 
>>>>>   (*/"1@:>:@(_& q:))24 360 4711
>>>>> 8 24 4
>>>>> 
>>>>> Mike
>>>>> 
>>>>> Sent from my iPad
>>> 
>> 
> 
> 
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