sorry, I was not sufficiently precise about my example
I meant to talk about atomic a only
if $ a is empty, then
+./ (, -) a
will work
Thanks for pointing out the lack of precision.
Am 16.05.20 um 11:46 schrieb Raul Miller:
I was talking about the implementation.
These are different results:
+./@(,-)4.57 4.34 4.44
8.88178e_16
+./@(,-)&.x:4.57 4.34 4.44
0.01
+./@(,-)&.:(*&1p1)4.57 4.34 4.44
5.65432e_16
The reason is that binary floating point cannot represent 5^_1 nor
5^_2 accurately.
Thanks,
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