Thanks Roger! That's exactly what I needed. The boxed solution is also
useful in a couple of instances.

Skip


On Sat, May 16, 2020 at 7:15 PM Roger Hui <rogerhui.can...@gmail.com> wrote:

> Hmm, you just want the keys: rotate each row so that the minimum item is
> first.
>
>    (n i."_1 <./"1 n)|."_1 n
> 1 3 2 4
> 1 2 3 4
> 1 2 3 4
> 1 3 2 4
> 1 3 2 4
> 1 2 3 4
> 1 2 3 4
> 1 3 2 4
>
>
> On Sat, May 16, 2020 at 5:11 PM Roger Hui <rogerhui.can...@gmail.com>
> wrote:
>
> >    ((n i."_1 <./"1 n)|."_1 n) </. n
> > ┌───────┬───────┐
> > │2 4 1 3│2 3 4 1│
> > │3 2 4 1│3 4 1 2│
> > │1 3 2 4│4 1 2 3│
> > │4 1 3 2│1 2 3 4│
> > └───────┴───────┘
> >
> > Rotate each row so that the minimum item is first, then use those rotated
> > rows as keys.
> >
> >
> > On Sat, May 16, 2020 at 4:44 PM Skip Cave <s...@caveconsulting.com>
> wrote:
> >
> >> I have run across this issue a few times in the past.
> >> The following 8x4 array has several rows that are 'rotational
> duplicates'.
> >>
> >> ]n=.8 4$2 4 1 3 2 3 4 1 3 4 1 2 3 2 4 1 1 3 2 4 4 1 2 3 1 2 3 4 4 1 3 2
> >>
> >> 2 4 1 3
> >>
> >> 2 3 4 1
> >>
> >> 3 4 1 2
> >>
> >> 3 2 4 1
> >>
> >> 1 3 2 4
> >>
> >> 4 1 2 3
> >>
> >> 1 2 3 4
> >>
> >> 4 1 3 2
> >>
> >>
> >> Is it possible to develop a verb that would find the rows that are
> >> rotational duplicates of each other. That is, find all the rows that
> would
> >> be the same, if each row was rotated some integer value in the first
> >> dimension. The output of the verb would be the same shape array, but
> with
> >> each duplicate row rotated such that they show as identical. Picking the
> >> 'standard' rotation for a set of rotational duplicates is up to the
> >> implementer.
> >>
> >>
> >> Skip
> >> ----------------------------------------------------------------------
> >> For information about J forums see http://www.jsoftware.com/forums.htm
> >>
> >
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
>
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