Sorry, 0 2 1 3 is obviously wrong,
I meant to say 0 3 2 1
Am 25.05.20 um 14:01 schrieb Hauke Rehr:
is this a more general task, or do you only ever
have exactly four items to arrange that way?
an easier way of doing what you did would be
take any solution, the 0 2 1 3&{ of it,
the |. of both, and apply (i.4) |."1 to all four.
That sould get you all possible 16 solutions
maybe someone else knows of a better way
to achieve this?
Am 25.05.20 um 13:47 schrieb Brian Schott:
I want all permutations of i. 4 for which 0 and 3 cannot be adjacent,
nor
can 1 and 2. My idea is to create a as follows to describe my situation.
]a =. 0 1 1 0,:i. 4
0 1 1 0
0 1 2 3
Next I created b and rotations on b to list the possibilities I can think
of. So I can think of 6 permutations. Are there more and is there a
better
way to generate the real qualifying permutations?
]b =. 0 1 3 2 ,:1 0 2 3
0 1 3 2
1 0 2 3
1|."1 b
1 3 2 0
0 2 3 1
_1|."1 b
2 0 1 3
3 1 0 2
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